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Q: What is the equation of a line in slope-intercept form for a line with slope 4 and y-intercept at (0 2)?

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To identify the slope in a linear equation, rearrange the equation into the form y = mx + b. The term m is the slope.

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what is the slope-intercept form of the equation 15y=10x+12

Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).

It is not an equation because it doesn't have an equal sign in it so to write it in slope-intercept form is impossible

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y = 2x + 1.

If you have the original equation, then I can show you how it can be rearranged into slope-intercept form. Slope intercept form will look like this: y = m*x + b.

y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0

The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3

Slope-intercept form is easy! The equation is y=mx+b (X)(X) O______O

When it is a line through the origin.

you say undefined

To identify the slope in a linear equation, rearrange the equation into the form y = mx + b. The term m is the slope.

Solve the equation for ' y '.

The general form of the slope-intercept equation is y = mx + b. In that equation, the slope is m and the y intercept is b.

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what is the yintercept for y=2/3x-8

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