2x(3x + 5)
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6x2 + 10x = 2x*(3x + 5)
6x2-5x-25 = (3x+5)(2x-5) when factored
I assume the question is to factor this problem? 6x2 + 14x - 12 can be factored to give (6x - 4)(x + 3) and then factor out a 2 to give 2(3x - 2)(x + 3) OR you could've factored with (3x - 2)(2x + 6), but the final answer would still be the same. 2(3x - 2)(x + 3)
6x2 + 11x + 3 = 6x2 + 9x + 2x + 3 = 3x(2x + 3) + 1(2x + 3) = (2x + 3)(3x + 1)
To find the factors of the quadratic expression 6x^2 + 13x - 5, we need to factorize it into two binomial expressions. We can do this by finding two numbers that multiply to the coefficient of x^2 (6) multiplied by the constant term (-5), which is -30, and add up to the coefficient of x (13). These numbers are 15 and -2. Therefore, the factored form of the expression is (2x + 5)(3x - 1).