6x2 + 10x = 2x*(3x + 5)
6x2+13x-5 = (2x+5)(3x-1) when factored
6x2-5x-25 = (3x+5)(2x-5) when factored
I assume the question is to factor this problem? 6x2 + 14x - 12 can be factored to give (6x - 4)(x + 3) and then factor out a 2 to give 2(3x - 2)(x + 3) OR you could've factored with (3x - 2)(2x + 6), but the final answer would still be the same. 2(3x - 2)(x + 3)
6x2 + 11x + 3 = 6x2 + 9x + 2x + 3 = 3x(2x + 3) + 1(2x + 3) = (2x + 3)(3x + 1)
6x2 + 10x = 2x(3x + 5)
6x2+5x+1 = (3x+1)(2x+1) when factored
6x2-17x+7 = (2x-1)(3x-7) when factored
Dividing all terms by 2 gives: 6x2+7x+2 = (2x+1)(3x+2) when factored
2x(3x + 5)
6x2-2x+36 = 5x2+10x 6x2-5x2-2x-10x+36 = 0 x2-12x+36 = 0 (x-6)(x-6) = 0 x = 6 or x = 6 It has two equal roots.
6x2 + 10x = 2x*(3x + 5)
Im assuming the "6x2" is supposed to be 6x squared. The factored form would be (2x+1) (3x-8)
6x2 + 5x - 6 is factored out to (2x + 3)(3x - 2).
6x2+23x+20=0x= .7275 and -4.5634Improved Answer:-6x2+23x+20 = (3x+4)(2x+5) when factored
It cannot be factored because the discriminant of b2-4ac is less than zero.
6x2+13x-5 = (2x+5)(3x-1) when factored