(X + 2)(X + 4) Factored
2x2 + 6x - 8 = 72 ∴ 2x2 + 6x + 64 =0 ∴ x2 + 3x + 32 = 0 This can not be factored, as x is not equal to any integer. Using the quadratic equation, we find that: x = -3/2 ± √119 / 2i
x2 - 7x = 8 x2 - 7x - 8 = 0Now find two numbers that multiply to equal -8, and add to equal -7.(1) * (-8) = -8(1) + (-8) = -7(x+1)(x-8) = 0 This is the factored form of x2 - 7x = 8You can then solve the equation if necessary, and get:x = -1 or x = +8
This is a quadratic equation question in finding the possible values of x x2 - 6x = - 8 x2 - 6x + 8 = 0 Factorise the expression in the equation: (x-2)(x-4) = 0 Therefore: x = 2 or x = 4
x2 + 6x + 8 =(x + 2)(x +4)
x2-6x+8 = (x-2)(x-4) when factored
If you mean: 8x2-56x-64 which becomes x2-7x-8 and is (x-8)(x+1) when factored
64-x2 = (8-x)(8+x) when factored
(X + 2)(X + 4) Factored
The expression 48x + 8 can be factored by finding the greatest common factor of the two terms, which in this case is 8. Therefore, we can rewrite the expression as 8(6x + 1). This is the factored form of 48x + 8.
x2 - 64 can be written as x2 - 82, which is of the form of a2 - b2.And a2 - b2 is factored as (a-b)(a+b).Therefore, x2 - 64 is factored as (x+8)(x-8).
-x2 + 6x + 16 = -(x2 - 6x - 16) = -(x - 8)(x + 2) = -(8 - x)(x + 2)
x2 - 6x - 16 = (x - 8)(x + 2)
x2 + 6x + 8 = (x + 4)(x + 2)
x3 - 5x2 + 6x - 8 = x3 - 4x2 - x2 + 4x + 2x - 8 = x2(x - 4) - x(x - 4) + 2(x - 4) = (x - 4)(x2 - x + 2) which has no further real factors.
Im assuming the "6x2" is supposed to be 6x squared. The factored form would be (2x+1) (3x-8)
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