[ x3 + 3x2 + 2x ] is a trinomial. It's factors are [ x, (x + 1), (x + 2) ] .
34 · m2 · x3
4x2 – 3 + x3 Apex Learning ;D
2x3 - 7 + 5x - x3 + 3x - x3 = 8x - 7
Factor the equation and solve for x in each part. x3-4x2-12x Factor out an x right away x (x² - 4x - 12) factor the trinomial x (x - 6) (x + 2) now solve each for y=0 x=0, (x-6=0), (x+2=0) The zeroes (solutions) to the equation are {-2 0 6 }■
x3 - 12x2 + 35x = x (x2 - 12x + 35) = x (x - 7) (x - 5)
Factor: x3 - 12x2 + 35x 1. Factor out a x: x(x2 - 12x + 35). 2. Factor x2 - 12x + 35 which is (x-5)(x-7). 3. Answer: x(x-5)(x-7).
x(x + 5)(x - 7)
Factor out an X X(X^2 - 12X + 35) factor quadratic equation X(X - 7)(X - 5) ------------------- fully factored
it is below 555 and above 200 * * * * * x3 - 2x2 + 35x = x*(x2 - 2x - 35) = x*(x + 5)*(x - 7)
x3 + 2x2 - 35x = x(x + 7)(x - 5)
x(x - 1)(x - 13)
x(x - 4)(x - 6)
x3 + 13x2 + 42x = x(x + 6)(x + 7).
It is: (x2 + 5x) (x + 8)
X3 - 4X2 - 45XX(X2 - 4X - 45)=============X is only common factor here.
x(x + 9)(x + 5)