The general term of the sequence 2, 4, 2, 4, 2, 4 is repeating number sequence.
10-2x for x = 0, 1, 2, 3, ... Since the domain of an arithmetic sequence is the set of natural numbers, then the formula for the nth term of the given sequence with the first term 10 and the common difference -2 is an = a1 + (n -1)(-2) = 10 - 2n + 2 = 12 - 2n.
36 Seems like: 1 4 9 16 25 is squared sequence: 1 2 3 4 5 So 6 squared will be 36.
Please note that (a) this is a sequence of square numbes, and (b) the sequence starts at 22.
It works out as -5 for each consecutive term
It is T(n) = n2 + 4*n + 2.
The nth term of the sequence is 3n - 2.
What is the value of the 8th term of the sequence 4, 8, 16, 32,?what is the answers?1,024,512,128or2,048.
16
2n+4/2 term 1 = 3 term 2 = 4 term 3 = 5 term 4 = 6
1 - 2 - 4 - 8 - 16 - 32 - 64 the sequence doubles
To work out the equation of a sequence, you should first look at the differences in the sequence. In this case, the differences between the numbers are -2, -2, -2. Thus the equation for the sequence is x-2n To work out x, you need to find what the "0th term" would be, or the term that would come before 4. In this case, it would be 4+2=6. Therefore, the equation for the nth term is 6-2n
The nth term of the sequence is 3n-8 and so the 30th term is 3*30 -8 = 82
The general term a(n) of the sequence is: a(n) = a(n - 1) * (n - 1), if n is even a(n) = a(n - 1) + (n - 1), if n is odd and a(1) = 2, of course. So the next term in the sequence would be 86 a(7) = a(6) + 6 = 80 + 6 = 86
The 'n'th term is [ 4 - 3n ].
The 'n'th term is [ 4 - 3n ].
The 'n'th term is [ 4 - 3n ].
The Nth term in the series is [ 2N ] .