1.8 meters. The ratio of object to shadow is 10:6. Therefore if the object is 3, the shadow is 1.8 ( 6/10x3).
It is approx 36.6 ft.
First find the angle of elevation by using the tangent ratio formula:tangent = opposite (the flagpole)/adjacent (the shadow)tangent = 30/12 = 68.19859051 degreesThen rearrange the formula to find the height of the mailbox:height of mailbox = 18*tangent 68.19859051 = 44.99999......Therefore: height of mailbox = 45 inches to the nearest inch.Or,Since we have two similar right triangles whose legs are the 30 feet flagpole and its 12 feet shadow, the length x of mailbox and its 18 inches shadow, we have:18 in/x = 12 ft/30 ft (cross multiply)(12)(x) = (30)(18 in)12x = 540 in (divide by 12 to both sides)x = 45 in
The flag pole would be 20 feet. (You can see that the shadows are twice as long.) At a given time of the day, the length of a shadow cast by any object will have the same relationship to its actual height as all other objects. Here the ratio is 5/10 = x/40 and multiplying both sides by 40, 20 = x.
To calculate that, you'd need to know the angle of the light source or the time of day or have some other object to compare it to.
25
Ten is to two as 40 is to x, yielding: 200ft.
21 ft how is the equation to give you this result
5
Not enough information has been given to solve this problem such as: What is the angle of elevation?
The statue is 6/2 = 3 times the length of its shadow. The flagpole is 3 times its shadow ie the flagpole is 3*10 = 30 metres.
pyramid
The flagpole is 15.92 metres, approx.
84 feet tall
It works out as: 42.353 feet tall rounded to 3 decimal places
First, find the ratio of fencepost-height : shadow which is 1.6 : 2.6 . This can also be written as a fraction, 1.6/2.6 . Then, multiply the flagpole's shadow by this ratio: 31.2 x 1.6/2.6 = 19.2 The flagpole is 19.2m high. The trigonometry way: On the imaginary right angled triangle formed by the fencepost and its shadow, let the angle at which the hypotenuse meets the ground = θ sinθ = 1.6/2.6 sinθ = /31.2 x/31.2 = 1.6/2.6 2.6x = 31.2 * 1.6 = 49.92 x = 19.2 The flagpole is 19.2m high.
When the light source is directly over it or at night.
The positioning of the sun throughout the day.