1.8 meters. The ratio of object to shadow is 10:6. Therefore if the object is 3, the shadow is 1.8 ( 6/10x3).
It is approx 36.6 ft.
To solve this problem, we can set up a proportion using the similar triangles formed by the flagpole and its shadow, and the mailbox and its shadow. The height of the flagpole to its shadow is 30 feet to 12 feet, which simplifies to 5:2. Using this ratio, we can determine the height of the mailbox by setting up the proportion 5/2 = x/1.5 (converting 18 inches to feet). Solving for x, the height of the mailbox would be 3.75 feet.
The flag pole would be 20 feet. (You can see that the shadows are twice as long.) At a given time of the day, the length of a shadow cast by any object will have the same relationship to its actual height as all other objects. Here the ratio is 5/10 = x/40 and multiplying both sides by 40, 20 = x.
To calculate that, you'd need to know the angle of the light source or the time of day or have some other object to compare it to.
25
Ten is to two as 40 is to x, yielding: 200ft.
21 ft how is the equation to give you this result
5
Not enough information has been given to solve this problem such as: What is the angle of elevation?
The statue is 6/2 = 3 times the length of its shadow. The flagpole is 3 times its shadow ie the flagpole is 3*10 = 30 metres.
pyramid
The flagpole is 15.92 metres, approx.
84 feet tall
It works out as: 42.353 feet tall rounded to 3 decimal places
First, find the ratio of fencepost-height : shadow which is 1.6 : 2.6 . This can also be written as a fraction, 1.6/2.6 . Then, multiply the flagpole's shadow by this ratio: 31.2 x 1.6/2.6 = 19.2 The flagpole is 19.2m high. The trigonometry way: On the imaginary right angled triangle formed by the fencepost and its shadow, let the angle at which the hypotenuse meets the ground = θ sinθ = 1.6/2.6 sinθ = /31.2 x/31.2 = 1.6/2.6 2.6x = 31.2 * 1.6 = 49.92 x = 19.2 The flagpole is 19.2m high.
When the light source is directly over it or at night.
The positioning of the sun throughout the day.