Oh, dude, the integral of ln(2) is just xln(2) + C, where C is the constant of integration. It's like the cool kid at the party that just hangs out and doesn't really do much. So yeah, that's the integral of ln(2) for ya.
integral of radical sinx
the cyclic integral of this is zero
non integral is type of numbers behaviour: i can say that set of numbers without any "holes inside" are integral and set of numbers with "holes inside are non integral. example : integral group "1..100" non integral group "1,4,8,67"
int(ln(x2)dx)=xln|x2|-2x int(ln2(x)dx)=x[(ln|x|-2)ln|x|+2]
The integral of 1 + x2 is x + 1/3 x3 + C.
In (x^(ln2)), ln2 is a constant, so the Power Rule can be used. d/dx (x^ln2)=(ln2)x^(ln2-1)
ln2^x = xln2. let ln2 = k (constant), then the differential = k. Hence d(ln2^x)/dx = ln2
NO! Lnx + Ln2= 2 + Lnx implies Ln2 = 2 which implies 2 = e2 which is simply not true.
LN2 i think :D
The derivative of 2^x is 2^x * ln2 so the derivative of 2^cosx * ln2 multiplied by d/dx of cox, which is -sinx so the derivative of the inside function is -sinx * 2^cosx *ln2. As to the final question, using the chain rule, d/dx (2^cosx)^0.5 will equal half of (2^cosx)^-0.5 * -sinx * 2^cosx * ln2
Very much
LN2 other know as liquid nitrogen is a solution that can make water hard
3lnx - ln2=4 lnx^3 - ln2=4 ln(x^3/2)=4 (x^3)/2=e^4 x^3=2e^4 x=[2e^4]^(1/3)
8
12
Assuming you mean 'logarithm to the base 'e' ( natural logarithm. On the calculator its symbol is 'ln'. Hence ;ln 2 = 0.69314718....
Integral in Tagalog: mahalaga