NO!
Lnx + Ln2= 2 + Lnx implies Ln2 = 2
which implies 2 = e2 which is simply not true.
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If: u = 1+lnx Then: x = (u-1)/(ln)
lnx + lnx +3 = (ln55)/4 2lnx +3 =(ln55)/4 8lnx + 12=ln55 8lnx=-12+ln55 lnx=(-12+ln55)/8 x=e^[(-12+ln55)/8]
i believe it is 7lnx, but don't quote me on it.
There are 2 interpretations of your question: First: e^[lnx + lny] =e^[ln(xy)] =xy Second: lny + e^(lnx) =lny + x