In (x^(ln2)), ln2 is a constant, so the Power Rule can be used. d/dx (x^ln2)=(ln2)x^(ln2-1)
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x = yy differentiate both sides with respect to x dx = (y * yy-1) dy dy/dx = y * yy-1 dy/dx = yy = x hence differentiate of y wrt x is x only
The derivative of 2^x is 2^x * ln2 so the derivative of 2^cosx * ln2 multiplied by d/dx of cox, which is -sinx so the derivative of the inside function is -sinx * 2^cosx *ln2. As to the final question, using the chain rule, d/dx (2^cosx)^0.5 will equal half of (2^cosx)^-0.5 * -sinx * 2^cosx * ln2
NO! Lnx + Ln2= 2 + Lnx implies Ln2 = 2 which implies 2 = e2 which is simply not true.
10x 10 is Base & x is exponent
The zero exponent rule basically says that any base with an exponent of zero is equal to one. For example: x^0 = 1A negative exponent is equivalent to 1 over a positive exponent.x^1 = x x^0 = 1x^-1 = 1/x