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What is the differentiation of y with respect to x for x equals y exponent y?
x = yy differentiate both sides with respect to x dx = (y * yy-1) dy dy/dx = y * yy-1 dy/dx = yy = x hence differentiate of y wrt x is x only
What is the derivative of the square root of 2 raised to the power of cos x?
The derivative of 2^x is 2^x * ln2 so the derivative of 2^cosx * ln2 multiplied by d/dx of cox, which is -sinx so the derivative of the inside function is -sinx * 2^cosx *ln2. As to the final question, using the chain rule, d/dx (2^cosx)^0.5 will equal half of (2^cosx)^-0.5 * -sinx * 2^cosx * ln2
When multiplying a variable with an exponent with a variable that doesn't have an exponent do you add the exponent or subtract it multiply it?
When multiplying a variable with an exponent by a variable without an exponent, you add the exponent of the first variable to the exponent of the second variable (which is considered to be 1). For example, if you multiply (x^2) by (x), the result is (x^{2+1} = x^3). This rule applies to variables with the same base.
Lnx plus Ln2 equals 2 plus lnx?
NO! Lnx + Ln2= 2 + Lnx implies Ln2 = 2 which implies 2 = e2 which is simply not true.
What has a base and a exponent?
10x 10 is Base & x is exponent
How do you differentiate ln 2 to the exponent x?
ln2^x = xln2. let ln2 = k (constant), then the differential = k. Hence d(ln2^x)/dx = ln2
How can one differentiate the function f(x) 3x3 - 2x2 5x - 1 without being a d3x dt3?
To differentiate the function f(x) 3x3 - 2x2 5x - 1 without being a d3x dt3, you can use the power rule for differentiation. This involves multiplying the coefficient of each term by the exponent of x and then decreasing the exponent by 1.
What is the differentiation of y with respect to x for x equals y exponent y?
x = yy differentiate both sides with respect to x dx = (y * yy-1) dy dy/dx = y * yy-1 dy/dx = yy = x hence differentiate of y wrt x is x only
What is the derivative of the square root of 2 raised to the power of cos x?
The derivative of 2^x is 2^x * ln2 so the derivative of 2^cosx * ln2 multiplied by d/dx of cox, which is -sinx so the derivative of the inside function is -sinx * 2^cosx *ln2. As to the final question, using the chain rule, d/dx (2^cosx)^0.5 will equal half of (2^cosx)^-0.5 * -sinx * 2^cosx * ln2
How do you solve 3 ln x - ln 2 equals 4?
3lnx - ln2=4 lnx^3 - ln2=4 ln(x^3/2)=4 (x^3)/2=e^4 x^3=2e^4 x=[2e^4]^(1/3)
How do you differentiate 2 to the power x with respect to x?
The answer is ln(2)2x where ln(2) is the natural log of 2. The answer is NOT f(x) = x times 2 to the power(x-1). That rule applies only when the exponent is a constant.
The n in x indicating the number of factors of x?
exponent exponent
How would 8 x 8 x 8 x 8 be written using an exponent?
8 with an exponent of four
When multiplying a variable with an exponent with a variable that doesn't have an exponent do you add the exponent or subtract it multiply it?
When multiplying a variable with an exponent by a variable without an exponent, you add the exponent of the first variable to the exponent of the second variable (which is considered to be 1). For example, if you multiply (x^2) by (x), the result is (x^{2+1} = x^3). This rule applies to variables with the same base.
How do you differentiate 2x with respect to x?
The answer is 2. 2x = 2x1 So you follow the usual rule about bring down the exponent and subtract one from it and you get 1*2x0= 2x0=2
What is x to 5th exponent multiplied by x to the 6th exponent?
( X5 ) x ( X6 ) = X(5+6) = X11
What is the n in xn indicating the number of factor of x?
exponent exponent
