x = yy differentiate both sides with respect to x dx = (y * yy-1) dy dy/dx = y * yy-1 dy/dx = yy = x hence differentiate of y wrt x is x only
The derivative of 2^x is 2^x * ln2 so the derivative of 2^cosx * ln2 multiplied by d/dx of cox, which is -sinx so the derivative of the inside function is -sinx * 2^cosx *ln2. As to the final question, using the chain rule, d/dx (2^cosx)^0.5 will equal half of (2^cosx)^-0.5 * -sinx * 2^cosx * ln2
NO! Lnx + Ln2= 2 + Lnx implies Ln2 = 2 which implies 2 = e2 which is simply not true.
10x 10 is Base & x is exponent
The zero exponent rule basically says that any base with an exponent of zero is equal to one. For example: x^0 = 1A negative exponent is equivalent to 1 over a positive exponent.x^1 = x x^0 = 1x^-1 = 1/x
ln2^x = xln2. let ln2 = k (constant), then the differential = k. Hence d(ln2^x)/dx = ln2
x = yy differentiate both sides with respect to x dx = (y * yy-1) dy dy/dx = y * yy-1 dy/dx = yy = x hence differentiate of y wrt x is x only
The derivative of 2^x is 2^x * ln2 so the derivative of 2^cosx * ln2 multiplied by d/dx of cox, which is -sinx so the derivative of the inside function is -sinx * 2^cosx *ln2. As to the final question, using the chain rule, d/dx (2^cosx)^0.5 will equal half of (2^cosx)^-0.5 * -sinx * 2^cosx * ln2
The integral of ln(2) is a constant multiple of x times the natural logarithm of 2, plus a constant of integration. In other words, the integral of ln(2) with respect to x is x * ln(2) + C, where C is the constant of integration. This integral represents the area under the curve of the natural logarithm of 2 function with respect to x.
The answer is ln(2)2x where ln(2) is the natural log of 2. The answer is NOT f(x) = x times 2 to the power(x-1). That rule applies only when the exponent is a constant.
3lnx - ln2=4 lnx^3 - ln2=4 ln(x^3/2)=4 (x^3)/2=e^4 x^3=2e^4 x=[2e^4]^(1/3)
exponent exponent
8 with an exponent of four
The answer is 2. 2x = 2x1 So you follow the usual rule about bring down the exponent and subtract one from it and you get 1*2x0= 2x0=2
( X5 ) x ( X6 ) = X(5+6) = X11
exponent exponent
6x6x5x6x3x2x3 in exponent form is 2 x 32 x 5 x 63