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When given the formula ac-d what is c?
ac - d is an expression: it is NOT a formula.
Are the medians of a triangle equidistant from each vertex?
Every triangle has three medians, just like it has three altitudes, angle bisectors, and perpendicular bisectors. The medians of a triangle are the segments drawn from the vertices to the midpoints of the opposite sides. The point of intersection of all three medians is called the centroid of the triangle. The centroid of a triangle is twice as far from a given vertex than it is from the midpoint to which the median from that vertex goes. For example, if a median is drawn from vertex A to midpoint M through centroid C, the length of AC is twice the length of CM. The centroid is 2/3 of the way from a given vertex to the opposite midpoint. The centroid is always on the interior of the triangle.
In line segment Ac is perpendicular to line segment CB and the measurement of angle CBD equals 125 degrees the the measurement of angle A equals?
The problem is meaningless without a diagram but I am guessing that ABC make a triangle and D is on the extension of AB beyond B. In that case we use the exterior angle theorem to get CBD = C + A, so 125 = 90 + A and A = 35.
How do you make a triangle with an area of 24?
Draw a straight line AB of any length x. Draw another line, parallel to AB and at a distance of 2*24/x units from it. Select any point on the second line and call that point C. Join AC and BC. Then triangle ABC will have an area of 24 square units.
Segment ab is represented by m segment bc is represented by n find the length of line segment ac when b is located between a and c?
Since B is located between A and C, you can just add the two lengths together, so AC = m + n.your segment looks like this:A----B----Cwhere AB=m, BC=n, and AC=m+n
11 abc is an equilateral triangle with side length equal to 50 cm bh is perpendicular to ac mn is parallel to ac find the area of triangle bmn if the length of mn is equal to 12 cm?
ABC is an equilateral triangle with side length equal to 50 cm. BH is perpendicular to AC. MN is parallel to AC. Find the area of triangle BMN if the length of MN is equal to 12 cm.
ABC is an equilateral triangle with side length equal to 50 cm. BH is perpendicular to AC. MN is parallel to AC. Find the area of triangle BMN if the length of MN is equal to 12 cm?
ABC is an equilateral triangle with side length equal to 50 cm. BH is perpendicular to AC. MN is parallel to AC. Find the area of triangle BMN if the length of MN is equal to 12 cm.
OC Is perpendicular to AB. What is the length of?
is perpendicular to . What is the length of ? A. 12.9 units B. 4.3 units C. 2.15 units D. 8.6 units
Ac and dc load line of BJT-explain?
when the dc supply given, dc load line lies in the Ic and Vcc. when the AC supply given, AC load line lies in the Ic and Vcc.
Show that of all line segments drawn from a given point not on it the perpendicular line segment is the shortest?
To show that the perpendicular line segment is the shortest among all line segments drawn from a given point not on it, we can use the Pythagorean theorem. Let the given point be P and the line segment be AB, with the perpendicular from P meeting AB at C. By the Pythagorean theorem, the sum of the squares of the two sides of a right triangle is equal to the square of the hypotenuse. In this case, PC is the hypotenuse, and AP and AC are the other two sides. Thus, AC (perpendicular line segment) will always be shorter than any other line segment AB drawn from point P.
Line BE is the bisector of segment AC. If AB 7 then AC .?
If line BE is the bisector of segment AC, it means that BE divides AC into two equal segments. Therefore, if AB is 7, then AC must be twice that length, making AC equal to 14.
In the given right triangle find the length of the hypotenuse AB if BC 6 and AC 5.?
The length is sqrt(61) units.
How many circles can pass through two given points?
Two points determine a unique line. Therefore, there are infinitely many circles that can pass through two given points. This is because a circle can be defined by its center, which can lie anywhere along the perpendicular bisector of the line segment connecting the two points.
How do you draw a line segment of root 12cm?
It is easiest to draw it using two right angled triangles.Draw a line AB that is 2 units long. From B, draw BC which is perpendicular to AB and 2 units long. Join AC. From C, draw CD which is perpendicular to AC (clockwise if BC is clockwise from AB, or anticlockwise if BC is anticlockwise) and make CD 2 uinits long. Then AD is a line segment which is sqrt(12) units long.
What would a triangle look like if ab plus ac equals bc?
It would be a straight line of length bc
Are the diagonals of a square are never perpendicular?
The diagonals of a square are always perpendicular. Proof: Without loss of generality, assume the square has side length 1 and one vertex is at the origin. The square ABCD is given by: A = (0,0) , B = (1,0) , C = (1,1) , D = (0,1) The diagonals are d1=AC and d2=BD. Finding equations for each of them yields d1 = x d2 = 1-x (you can double check this) So, the relative slopes are 1 and -1. Since their product is -1, they are perpendicular.
In triangle abc given that angle a equals 57 angle b equals 73 and ab equals 24cm find the length of ac?
The sum of the angles inside a triangle is equal to 180°. We are told that angle a is 57°, and that angle b is 73°. This tells us that angle c is is (180 - 57 - 73)°, or 50°. We are also given the length of side ab, 25cm. With that, we can use the sine rule to calculate the length of side ac: sin(b) / |ac| = sin(c) / |ab| ∴ sin(73°) / |ac| = sin(50°) / 24cm ∴ |ac| = 24cm · sin(73°) / sin(50°) ∴ |ac| ≈ 29.96cm
