It is: (2x-5)(2x-5) = 2.5 square cm when solved as a quadratic equation
a rectangle has a length of 2x-5 units and a width of x-3 units. what is the area, in square units, of the rectangle?
The formula for finding the area of a rectcngle is: L * W = A Let x represent the width and 2x represent the length (twice the width). Set up the equation and solve: 2x * x = 50 (then simplify) 2x² = 50 (then divide both sides to find the value of x²) x² = 25 (then find the square root of 25 to solve for x) x = 5 the width (x) = 5, and the length (2x) = 10
Say the radius of the circle is x. This makes the area of the circle pi x2. Since the length of the square's sides is the diameter of the circle, 2x, its area is 2x * 2x = 4x2. The percentage occupied by the circle is the area of the circle divided by the area of the square times 100 pi/4 x 100; pi/4 x 100 = 100pi/4 = 25pi = 78.6%.
First we have to find the width. Let the width be x: 2(12+x) = 30 24+2x = 30 2x = 30-24 2x = 6 x = 3 So the width is 3 units Area = length*width = 12*3 = 36 square units
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Rectangular Prisim 2x(area of front)+2x(area of side)+x2(area of length) Cube 2x(area of side)+2x(area of side)+2x(area of side)
4x2 - 4xy + y2 = (2x - y)2 so the length of the side of the square must be 2x-y.
The perimeter is the sum of the sides. So if a square has a side of length 1, its perimeter is 1+1+1=1 = 4 If a square has a side doubled to length 2, its perimeter is 2+2+2+2 = 8, or double what it was before. Mathematically, if each side is length x it perimeter is x + x + x = X = 4x If each side is length 2x, its perimeter is 2x +2x+2x+2x = 8x
(2x-7)(2x-7) = area 4x2-28x+49 = area
It is: (2x-5)(2x-5) = 2.5 square cm when solved as a quadratic equation
a rectangle has a length of 2x-5 units and a width of x-3 units. what is the area, in square units, of the rectangle?
Each side of the square is 2x+1.5 and its area is (2x+1.5) squared
4(2x+3) [there's 4 equal sides] 4(2x)+4(3) 8x+12
If that means (2 times 4) then the area of the square is 8*8 = 64 square cm
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Let the width = X. The length is twice the width plus 5. So the length must be 2X + 5. Area = 63 ft squared = X multiplied by 2X + 5 = 2X squared + 25. 2X squared = 63 - 25 = 38 2X = square root of 38. Therefore the width is the square root of 38 divided by 2 and the length is the square root of 38 plus 5.