Yes, you can. An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2.
Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd. ========================== You've just read a truly impressive answer to a question slightly different from the one that was asked. The part of the question that comes after "Why if ..." is a false statement. If you multiply odd number with another number, the result is odd number ONLY if the nother number is also odd number.
(101) x (22) = 2,222
An even number is any number that has '2' as a factor.When you multiply two numbers, you multiply all the factors of both of them.If '2' was a factor of either number, then it's a factor of their product.
If you multiply anything by 2 it always comes out even. So if people make 35 handshakes, we multiply it by 2 and we get 70 people. This will work with any different number of handshakes, odd or even.
An odd number times an odd number is an odd number no matter which 2 odds you multiply.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. Odd times even is even.
For 2 to be a factor, the number has to be even. If you multiply two odd numbers together, you get an odd number. 7 is odd, so if I multiply it by any odd number, I will get a number that doesn't have 2 as a factor (e.g. 7x5=35 which doesn't have 2 as a factor). Thus, the answer to the question is "no," not all multiples of 7 have 2 as a factor.
Yes, you can. An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2.
yes, the product of 2 odd numbers is always an odd number. Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd.
Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd. ========================== You've just read a truly impressive answer to a question slightly different from the one that was asked. The part of the question that comes after "Why if ..." is a false statement. If you multiply odd number with another number, the result is odd number ONLY if the nother number is also odd number.
(101) x (22) = 2,222
An even number is any number that has '2' as a factor.When you multiply two numbers, you multiply all the factors of both of them.If '2' was a factor of either number, then it's a factor of their product.
you would get an even number; 2x1=2 2x3=6 2x5=10
If you multiply anything by 2 it always comes out even. So if people make 35 handshakes, we multiply it by 2 and we get 70 people. This will work with any different number of handshakes, odd or even.
No.
For 'odd' prime numbers this is true, but '2' is also a prime number , so you will have an even answer. Remember when multiplying even X even = even even X odd = even odd X even = even odd x odd = odd.