Appears we are adding 6 each time. So the nth term is a_(n-1)+6 where n-1 is a subscript of a.
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Well, darling, it looks like this sequence is increasing by 6 each time. So, to find the nth term, you just multiply n by 6 and subtract 5. In this case, the nth term would be 6n - 5. Math made easy, just like stealing candy from a baby.
To find the nth term in a sequence, we first need to identify the pattern or rule governing the sequence. In this case, the common difference between each term is 6 (7-1=6, 13-7=6, 19-13=6). Therefore, the nth term can be expressed as Tn = 1 + 6(n-1), where n represents the position of the term in the sequence.
Oh, dude, you just add 6 to each term to get the next one. So, like, if you want the 4th term, you just add 6 three times to 1, which gives you 19. Easy peasy lemon squeezy.
The nth term is 4n-1 and so the next term will be 19
nth term is n squared plus three
The nth term is 6n+1 and so the next term will be 31
The nth term is: 2n+7 and so the next number will be 19
It is: nth term = 7n-9