The order of a group is the same as its cardinality - i.e. the number of elements the set contains. The order of a particular element is the order of the (cyclic) group generated by that element - i.e. the order of the group {...a-4, a-3, a-2, a-1, e, a, a2, a3, a4...}. If these powers do not go on forever, it will have a finite order; otherwise the order will be infinite.
The order of a group is the same as its cardinality - i.e. the number of elements the set contains. The order of a particular element is the order of the (cyclic) group generated by that element - i.e. the order of the group {...a-4, a-3, a-2, a-1, e, a, a2, a3, a4...}. If these powers do not go on forever, it will have a finite order; otherwise the order will be infinite.
If you mean in the group {1, -1, i, -i, j, -j, k, -k}, the identity element is 1.
They would form an ionic compound.
some examples of symbols for permuation groups are: Sn Cn An These are the symmetric group, the cyclic group and the alternating group of order n. (Alternating group is order n!/2, n>2) One other is the Dihedral group Dn of order 2n.
The abelian groups of order 24 are C3xC8, C2xC12, C2xC2xC6. There are other 12 non-abelian groups of order 24
The order of an element in a multiplicative group is the power to which it must be raised to get the identity element.
The order of a group is the same as its cardinality - i.e. the number of elements the set contains. The order of a particular element is the order of the (cyclic) group generated by that element - i.e. the order of the group {...a-4, a-3, a-2, a-1, e, a, a2, a3, a4...}. If these powers do not go on forever, it will have a finite order; otherwise the order will be infinite.
The order of a group is the same as its cardinality - i.e. the number of elements the set contains. The order of a particular element is the order of the (cyclic) group generated by that element - i.e. the order of the group {...a-4, a-3, a-2, a-1, e, a, a2, a3, a4...}. If these powers do not go on forever, it will have a finite order; otherwise the order will be infinite.
Let ( G ) be a finite group with order ( |G| ), and let ( g \in G ) be an element of finite order ( n ). The order of ( g ), denoted ( |g| ), is the smallest positive integer such that ( g^k = e ) for some integer ( k ), where ( e ) is the identity element. The subgroup generated by ( g ), denoted ( \langle g \rangle ), has order ( |g| = n ). By Lagrange's theorem, the order of any subgroup divides the order of the group, thus ( |g| ) divides ( |G| ).
"Carbonate" is not an element or an element group; instead, it is a polyatomic anion and is one of a large group of oxyanions.
chlorine, 17, 17 in order you asked.
The order of an elementg in a group is the least positive integer k such that gk is the identity.Now look at the same group, we know there exists an element h such that gh=hg=e where e is the identity. This must be true because existence of inverses is one of the conditions required for a set to be a group. So if gk=e and gh=e, then gk =gh and we see the relation between k, the order and h the inverse in the group.
The element "Cadmium" is in group number 12.
If we look at the periodic table, we can see that the first element in Group I is Hydrogen.
In abstract algebra, a generating set of a group is a subset of that group. In that subset, every element of the group can be expressed as the combination (under the group operation) of finitely many elements of the subset and their inverses.
The group name for the element Pb is "group 14" or "group IV."
Group A sir.