If you mean: 7y = -7(x-4) then y = -x+7 whereas -1 is the slope and 7 is the y intercept
Points: (8, 8) and (1, 2) Slope: (8-2)/(8-1) = 6/7 Equation: y-8 = 6/7(x-8) => 7y-56 = 6x-48 => 7y = 6x-48+56 Slope intercept form: 7y = 6x+8
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They are negative reciprocals. So if the slope of a line is x, the slope of the perpendicular line is -1/x
You can always find out the slope of a line by looking at the number before the variable. As you can see, there is no number in front of x, so how is there a slope? If X is ever alone, that means that there is one X, so the slope of the line is 1.
14y - 2x = 28 ie 7y - x = 14 ie 7y = x + 14 or y = (1/7)x + 14 The slope is the coefficient of x, or 1/7
If the equation is x + 7y = 14 then the slope is -1/7 If the equation is x + y7 = 14, then the slope is 7(14 - x)-8
7y = - 14 x + 49 divide with 7 on both sides , then we get y = - 2 x + 7 which is the form y = m x + c ( slope intercept form ) where m = slope and c = intercept so slope m = -2 for given line
if: 6x - 7y = 10 then -7y = 10 - 6x y = 6x/7 - 10/7 The slope is now the coefficient of x, which is 6/7.
If you mean: 7y = -7(x-4) then y = -x+7 whereas -1 is the slope and 7 is the y intercept
-7y + 21 = 3x Add '7y' to both sides 21 = 3x + 7y Subtract '3x' from both sides 21 - 3x = 7y 'Swop around'. 7y = -3x + 21 Divide both sides by '7' y = -(3/7)x + 3 The slope of a straight line is the coefficient of 'x' In this case it is ' -3/7'.
The slope intercept form is: y = mx + b 9x + 7y = 15 9x - 9x + 7y = 15 - 9x 7y = - 9x + 15 y = -(9/7)x + 15/7
The simplest way is to rewrite the equation in the standard for: y = mx + c. Then the slope is m. 8x - 7y = 56 7y = 8x - 56 y = 8/7 * x - 8 So the slope is 8/7
Points: (8, 8) and (1, 2) Slope: (8-2)/(8-1) = 6/7 Equation: y-8 = 6/7(x-8) => 7y-56 = 6x-48 => 7y = 6x-48+56 Slope intercept form: 7y = 6x+8
The slope of the line is (6-3)/(14-7) = 3/7 The equation is: y - 3 = (3/7)(x - 7) → y - 3 = (3/7)x - 3 ← y = (3/7)x
In the equation: y = mx + c m is the gradient (or slope) and c is the point at which the line crosses the y-axis. Therefore, we are looking to determine m. Your equation is: 4x + 7y = 28 Let's rearrange this as follows: 7y = -4x + 28 Now divide by 7 throughout: y = (-4/7)x + 4 Therefore, m = -4/7, or -0.5714
The slope m' of a line perpendicular to a line with slope m is such that m'm = -1 → m' = -1/m A line with slope m' through point (X, Y) has equation: y - Y = m'(x - X) → The line perpendicular to 7x - 8y = 12 through p (-3, 1) is found: 7x - 8y = 12 → 8y = 7x - 12 → y = (7/8)x - 3/2 → The slope of 7x - 8y = 12 is m = 7/8 → The slope of the perpendicular line is m' = -1/m = -1/(7/8) = -8/7 → The line through P with this slope m' is: y - 1 = -8/7(x - -3) → y = (-8/7)x - 24/7 + 1 → y = (-8/7)x - 17/7 This can be rearranged into: y = (-8/7)x - 17/7 → 7y = -8x - 17 → 7y + 8x + 17 = 0