The slope m' of a line perpendicular to a line with slope m is such that m'm = -1 → m' = -1/m
A line with slope m' through point (X, Y) has equation: y - Y = m'(x - X)
→ The line perpendicular to 7x - 8y = 12 through p (-3, 1) is found:
7x - 8y = 12
→ 8y = 7x - 12
→ y = (7/8)x - 3/2
→ The slope of 7x - 8y = 12 is m = 7/8
→ The slope of the perpendicular line is m' = -1/m = -1/(7/8) = -8/7
→ The line through P with this slope m' is:
y - 1 = -8/7(x - -3)
→ y = (-8/7)x - 24/7 + 1
→ y = (-8/7)x - 17/7
This can be rearranged into:
y = (-8/7)x - 17/7
→ 7y = -8x - 17
→ 7y + 8x + 17 = 0
y equals -1/3x plus 4/3
2y = -6x +8 y = -3x +4 The slope of the perpendicular is the positive reciprocal of -3 ahich is 1/3. So the equation is: y = 1/3x +5 If you mean that the y intercept is -5 then just change it.
rgdgfh
If the original line has the equation 2y = 7x then this can be written as y = 3.5x and the slope of this line is thus 3.5. Two straight lines are perpendicular if the product of their gradients is -1. Let m be the slope of the perpendicular line then, 3.5m = -1 : m = -1/3.5 = -2/7 The equation of the perpendicular line is thus, y = -2/7 * x + b where b is the intercept. As b = 5 then the equation becomes y = -2/7*x + 5 We can multiply by 7 to eliminate the fraction, 7y = -2x + 35 and re-order the terms to become 7y = 35 - 2x
The x-intercept is equal to -b/m.
There is no y-intercept or slope for this given equation, because its graph is a vertical line perpendicular to the x-axis.
y equals -1/3x plus 4/3
y = x
Convert the equation 2y = 5x - 4 into standard form then y = 2.5x - 2. Two straight lines are perpendicular if the product of their gradients is -1. Let the equation of the perpendicular line by y = mx + b. Then, 2.5m = -1 : m = -1/2.5 The y intercept occurs when x = 0. Then -3 = 0 + bc : b = -3 The equation of the perpendicular line is y = -1/2.5x -3 or 5y = -2x -15
y=-x+4
5x - 10 = -20This equation can be restated as 5x = -10 : x = -2This is the equation of a straight line perpendicular to the x axis and passing through the point x = -2. There is no y intercept and the slope is indeterminate.
The equation of a line that is perpendicular to 3y = -x + 9 and that has a y intercept of 6 is y = 3x + 6. The slope of the first line is -1/3, from the slope-intercept form y = mx + b, or y = -x/3 + 3. The perpendicular slope is 3, by negating and inverting -1/3. Add the intercept to the slope-intercept form and you get y = 3x + 6.
2y = -6x +8 y = -3x +4 The slope of the perpendicular is the positive reciprocal of -3 ahich is 1/3. So the equation is: y = 1/3x +5 If you mean that the y intercept is -5 then just change it.
If -14 is the y intercept then it is: y = -1/13x -14
Slope is zero y-intercept is -7 there is no x-intercept for this equation
rgdgfh
Solving the equation for "y" gives you the slope-intercept form.