If you mean y = -8 then it has no slope and it is a straight line that is parallel to the x axis cutting through the y axis at -8
15
x - 4y = 3 is the slope of a line perpendicular to line whose equation is y -5 3x plus 8 3.
The slope intercept form is y=mx+b where m is the slope and b is the y intercept y=2x-8.
Equation: y-3 = -5(x-6) => y = -5x+33
There is no equation there but the slope of the line is the number that multiplies x in the straight line equation y = mx + b whereas m is the slope and b is the y intercept
15
-12
13
From the given information the straight line equation is: y = 7x-8
8
To find the slope of the line described by the equation ( y - x + 8 = 0 ), we can rearrange it into slope-intercept form ( y = mx + b ). Adding ( x ) and subtracting ( 8 ) gives us ( y = x - 8 ). In this form, the slope ( m ) is the coefficient of ( x ), which is 1. Therefore, the slope of the line is 1.
If the slope is 7 and the coordinate is (8, 5) then the straight line equation is y=7x-51
It is 8 and the y intercept is 8
To find the equation of the line with slope ( m = 8 ) that passes through the point ((-3, -6)), we can use the point-slope form of the equation of a line: ( y - y_1 = m(x - x_1) ). Substituting the values, we get: [ y + 6 = 8(x + 3). ] Simplifying this, the equation of the line is ( y = 8x + 18 ).
y=x+8 is a linear equation. Y is the Y point on a graph, X is the slope, and 8 is the y intercept
13
Use the slope intercept form equation, y=mx+b. Plug in -2 for m and 8 for b. Final equation: y=-2x+8