If you mean points of: (-1, -1) and (3, 5) then the slope is 3/2 or 1.5
If you mean: (2, 13) and (-4, -11) then the slope is 4 and both equations will have the same slope of 4 but with different y intercepts
To find the equation of a line passing through two points, we first calculate the slope using the formula (y2 - y1) / (x2 - x1). Given the points (1, 11) and (-2, 2), the slope is (2 - 11) / (-2 - 1) = -9 / -3 = 3. Next, we use the point-slope form of a linear equation, y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line. Substituting (1, 11) as the point and 3 as the slope, we get the equation y - 11 = 3(x - 1). Simplifying, we get y = 3x + 8 as the equation of the line.
Slope intercept form is y = mx + b. Point slope form is y - y1 = m(x - x1). Here is an example of changing slope-intercept form to point-slope form: Change y = 3x + 2 to point slope form: y = 3x + 2 Subtract 2 from each side: y -2 = 3x The equation y-2 = 3x is in point-slope form. It can be rewritten as y-2 = 3(x-0), showing that the line passes through the point (0,2), but is doesn't need to be. (The x1 and y1 represent one point on the line, it doesn't matter which one. Therefore, there are many different equations for the same line in point-slope form. For example, the equation y -2 = 3x is the same line as the equation y - 11 = 3(x - 3), which is the same line as the equation y + 4 = 3(x + 2).)
The equation of a line with slope m through a point (x0, y0) has equation: y - y0 = m(x - x0) Thus the equation of the line with slope 2 through the point (4, -3) has equation: y - (-3) = 2(x - 4) → y + 3 = 2x - 8 → y = 2x - 11
it should actually look like this- 5x - y = 11 sorry
If you mean points of: (-1, 1) and (9, 4) then the slope works out as 3/10
Slope: 2/3 Point: (9, 11) Equation: 3y = 2x+15
If you mean: (2, 13) and (-4, -11) then the slope is 4 and both equations will have the same slope of 4 but with different y intercepts
-24
If the points are (-7, 2) and (4, 6) then the slope of the line is 4/11
To find the equation of a line passing through two points, we first calculate the slope using the formula (y2 - y1) / (x2 - x1). Given the points (1, 11) and (-2, 2), the slope is (2 - 11) / (-2 - 1) = -9 / -3 = 3. Next, we use the point-slope form of a linear equation, y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line. Substituting (1, 11) as the point and 3 as the slope, we get the equation y - 11 = 3(x - 1). Simplifying, we get y = 3x + 8 as the equation of the line.
Use the point slope form. Y - Y1 = m(X - X1) Y - 11 = -3[X - (-3)] Y - 11 = -3X + 9 Y = -3X + 20
Slope intercept form is y = mx + b. Point slope form is y - y1 = m(x - x1). Here is an example of changing slope-intercept form to point-slope form: Change y = 3x + 2 to point slope form: y = 3x + 2 Subtract 2 from each side: y -2 = 3x The equation y-2 = 3x is in point-slope form. It can be rewritten as y-2 = 3(x-0), showing that the line passes through the point (0,2), but is doesn't need to be. (The x1 and y1 represent one point on the line, it doesn't matter which one. Therefore, there are many different equations for the same line in point-slope form. For example, the equation y -2 = 3x is the same line as the equation y - 11 = 3(x - 3), which is the same line as the equation y + 4 = 3(x + 2).)
If you mean y = 11x then the slope is 11
Points: (6, 8) and (4, -3) Slope: (-3-8)/(4-6) = 11/2 or 5.5
y - 9 = 10(x - 2) or y = 10x - 11
11