If we plot these two points on a graph, we see that it is a straight horizontal line. Slope is found by taking rise/run. Now because the rise is 0, the slope of this line is 0.
Points: (-1, -1) and (-3, 2) Slope: -3/2
2
If: 11x-8y = 32 Then: -8y = -11x+32 And: y = 1.375x-4 in slope-intercept form
|32 - 132| = |-100| = 100 |32 - 132| = |-100| = 100
y + 2x = 3xy + 2 - 2 = 3x - 2y = 3x - 2 this is the slope-intercept form of the equation of the line, y = mx + b, where slope m is 3, and the y-intercept b is -2.To find the x-intercept substitute 0 for y into the equation.y + 2 = 3x0 + 2 = 3x2/3 = 3x/32/3 = xThus the x-intercept is 2/3.
It has no slope.
Points: (-1, -1) and (-3, 2) Slope: -3/2
Points: (-1, -1) and (-3, 2) Slope: -3/2
If you mean points: (-3, -5) and (3, 2) then the slope works out as 7/6
Points: (12, 8) and (17, 16) Slope: 8/5 Equation: 5y = 8x-32
32
To find the slope of the line perpendicular to the given equation, we first need to determine the slope of the original line. The equation (-4x + 3y = -32) can be rearranged into slope-intercept form (y = mx + b). Solving for (y), we get (3y = 4x - 32) or (y = \frac{4}{3}x - \frac{32}{3}), which has a slope of (\frac{4}{3}). The slope of a line perpendicular to this would be the negative reciprocal, which is (-\frac{3}{4}).
To find the slope between the points (32) and (10), we need to know their coordinates. Assuming these points are (32, y1) and (10, y2), the slope ( m ) can be calculated using the formula ( m = \frac{y2 - y1}{10 - 32} ). Without specific y-values, the slope cannot be determined. Please provide the complete coordinates for an accurate calculation.
2
THE QUESTION IS ACTUALLY WORDED. FIND THE EQUATION OF THE LINE THAT CONTAINS THE POINTS P1(-7,-4) AND P2(2,-8). ALGEBRA
30
If you mean points of: (-1, -4) and (3, 2) Slope: 3/2 Equation works out as: 2y = 3x-5