y -5 = -3(x -4) y = -3x+12+5 y = -3x+17 in slope intercept form
y=3x+b -2=3*5+b b=-17 y=3x-17
If you mean: y - 5 = -3(x - 17) then:The slope is -3 and the line passes through the point (17, 5).It can be rearranged into y = -3x + 56 to also give the slope of -3 and the y-intercept of 56
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Get in slope intercept form. 3X + 5Y = 15 5Y = -3X + 15 Y = -3/5X + 3 -3/5 is the slope of this line and the line parallel to this line
y -5 = -3(x -4) y = -3x+12+5 y = -3x+17 in slope intercept form
3X + 5Y = 155Y = -3X + 15Y = (-3/5)X + 3The slope of this line is -3/5.The slope of a line perpendicular to it is 5/3.
y=3x+b -2=3*5+b b=-17 y=3x-17
A linear equation in the form y = mx + c has slope m Any line parallel to 3x + 9y = 5 has the same slope 3x + 9y = 5 → 9y = -3x + 5 → y = (-3/9)x + 5/9 → y = -⅓x + 5/9 → Every line parallel to 3x + 9y = 5 has slope -⅓.
Do you mean: y = -3x+5 then if so the slope is -3 and the y intercept is 5
If you mean: y - 5 = -3(x - 17) then:The slope is -3 and the line passes through the point (17, 5).It can be rearranged into y = -3x + 56 to also give the slope of -3 and the y-intercept of 56
A linear equation in the form y = mx + c has slope m The slope m' of a line perpendicular to a line with slope m is such that m'm = -1 → m' = -1/m 3x + 9y = 5 → 9y = -3x + 5 → y = (-3/9)x + 5/9 → y = -⅓x + 5/9 → its slope is -⅓ → perpendicular lines have slope m' = -1/(-⅓) = 3 → Every line perpendicular to 3x + 9y = 5 has slope 3.
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Get in slope intercept form. 3X + 5Y = 15 5Y = -3X + 15 Y = -3/5X + 3 -3/5 is the slope of this line and the line parallel to this line
When the equation of a line is written in standard form: y = mx + c, the slope of the line is m. Here, y = 3x + 5 so slope = 3
As for example in the straight line equation of y=3x+5 the slope is 3 and the y intercept is 5
The line is (y + 5) = -3*(x - 4) that is, y + 5 = -3x + 12 or y = 7 - 3x.