The only possible answer is:
x=18
If the square root of 6x-2=4 than we can square both sides and we have 6x-2=16 or 6x=18 and the solution set is the set that contains the number 3.
There is no equals sign visible but, taking the equation to be8x2 + 2x + 1 = 0,the solutions are the complex conjugate pair, -1.25 ± 0.330719*i where i is the imaginary square root of -1.
Using the quadratic formula, I found the solution set is x=2,x=-9
x
The solution set is x = 5n + 3 where n is any integer.
If the square root of 6x-2=4 than we can square both sides and we have 6x-2=16 or 6x=18 and the solution set is the set that contains the number 3.
x = 2 + 2ix = 2 - 2iwhere i is the imaginary square root of -1.
The square root of zero is zero and the square root of one is one. No other real numbers have square roots equal to themselves. In other words, the solution set to x=x2 is {0,1}
Set it up and solve:10x² - 64 = 36 + 6x² (then separate like terms)10x² - 6x² = 36 + 64 (then simplify)4x² = 100 (then divide by 4 to solve for x²)x² = 25 (now solve for the square root of 25)x = 5 (solution)NOTEThere is another solution: x = -5When you take square roots, ALWAYS remember to include the possibility that the solution is the negative root.
What is the solution set of 2x2 + x = 15
Reading this as: 4x2-6=2x2 This implies that: -6=-2x2 3=x2 x=sqrt(3) and x=-sqrt(3) So x can equal plus or minus the square root of 3
The set is [ 16 ] .
There is no equals sign visible but, taking the equation to be8x2 + 2x + 1 = 0,the solutions are the complex conjugate pair, -1.25 ± 0.330719*i where i is the imaginary square root of -1.
I will assume you mean,X2 - 16 = 0X2 = 16take square root each sideX = (+/-) 4=========(-4, 0) and (4, 0)----------------------
The geometric mean of the set { 12, 16 } is the square root of 192, or approximately 13.856.To find a geometric mean from a set of numbers, you find the product of the members of the set, and then take the nth root of that product, where n equals the count of the number of members in the set.Given the set { 12, 16 } our count is 2. Therefore, we will be taking the 2nd root (or "square root.")SQRT( 12 * 16 )SQRT( 192 ) or approximately 13.856
The square root of 121 is rational, an integer, and a natural number.
The sets of numbers that are the Square root of 5 are: 25 125