If the square root of 6x-2=4 than we can square both sides and we have 6x-2=16 or 6x=18 and the solution set is the set that contains the number 3.
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10x2 - 64 = 36 + 6x2 Combine like terms: 4x2 = 100 Divide both sides by 4: x2 = 25 Take square roots: x = -5 or +5
This doesn't factor neatly. Applying the quadratic equation, we find two imaginary solutions: (-17 plus or minus the square root of -671) divided by 12x = -1.4166 + 2.158638974498103ix = -1.4166 - 2.158638974498103iwhere i is the square root of negative one.
6x2+13x-5 = 0 (2x+5)(3x-1) = 0 x = -5/2 or x = 1/3
10x2 - 64 = 36 + 6x2; whence, 4x2 - 100 = 0, x2 = 25, and x = ±5.
No. 6 x 2 = 2 x 6 is.