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There is no equation (nor inequality) in the question, only an expression. Expressions cannot have solutions.
4x2-4x-3 = 0 (2x-3)(2x+1) = 0 x = 3/2 or x = -1/2
For example, if you have (0, 6) or (3, 1). Which of them is a solution to y - 2x = 6? Check (0, 6): y - 2x = 6, substitute 0 for x, and 6 for y into the equation 6 - 2(0) =? 6 6 - 0 =? 6 6 = 6 True, then (0, 6) is a solution. Check (3, 1): y - 2x = 6, substitute 3 for x, and 1 for y into the equation 1 - 2(3) =? 6 1 - 6 =? 6 -5 = 6 False, then (3, 1) is not a solution.
Blue is not a solution.
if you mean 2x-1*3 then the answer is: 2x-3
It could be the solution to some quadratic inequalities: for example x2 + 2x - 3 > 0 whose solution is x < -3 or x > 1.
2x - 3 - 8 = 1. 2x - 11 = 1. 2x = 12.x = 6!
x = 5
Yes if you mean (1, 3) and 3y = 2x+1
2
2x2+5x-3 = 0 (2x-1)(x+3) = 0 x = 1/2 or x -3
2x - 3 = 2x - 52x = 2x - 22x - 2x = -20 =/= -2Zero is not equal to -2 so the answer is no solution.
I assume you mean 3y+2x+1. So sub in the points and see. The 1 is x and the -3 is y. 3(-3) + 2(1) + 1. Does this equal 0? -9+2+1 equals -6, so no, it is not a solution. For example, if your point is (1,-1), this would be a solution.
7 and (-3/2)
x=-2
4x2-4x-3 = 0 (2x-3)(2x+1) = 0 x = 3/2 or x = -1/2
(2x - 10) + 7 = 52x - 3 = 52x = 8x = 4
No, to check if the values are a solution, substitute x=1 and y=3 into the equation and see if it holds true. In this case, when x=1 and y=3, the equation becomes 3(3) ≠ 2(1) + 1, which simplifies to 9 ≠ 3. So, 1,3 is not a solution to the equation 3y = 2x + 1.