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What is the straight line equation passing through -2 -3 that is perpendicular to 4x plus 3y -5 equals 0 showing all work?
Wiki User
∙ 10y ago
The basic steps are:
- Solve the given equation for y. Since this puts the equation in slope-intercept form, you can immediately tell its slope from that equation.
- Divide -1 by this slope. This gives you the slope of the perpendicular line.
- Look up the equation for a line that has a given slope and passes through a given point. Apply it in this case.
Another Answer:-
If: 4x+3y-5 = 0
Then: 3y = -4x+5 => y = -4/3x+5/3
Perpendicular slope: 3/4
Equation: y--3 = 3/4(x--2) => 4y--12 = 3(x--2) => 4y = 3x-6
Or as: 3x-4y-6 = 0
Wiki User
∙ 10y ago
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