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Any number multiplied by zero will always give the result of zero.
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Find two number whose sum is 27 and product is 182?
Let the first number be x and the second number is 27 − x. [As the sum of both the numbers is 27] Therefore, their product = x (27 − x) It is given that the product of these numbers is 182. x (27 – x) = 182 x2 + 27x - 182 = 0 Changing the signs on both sides we get,x2 - 27x + 182 = 0 Factorizing we get , 13 and 14 are the numbers whose sum is 27 and product is 182 x2 – 13x – 14x + 182 = 0 = x(x – 13) – 14 (x – 13)= 0 = (x – 13) (x – 14) = 0 Either x – 13 = 0 or x − 14 = 0 i.e., x = 13 or x = 14 If first number = 13, then Other number = 27 − 13 = 14 If first number = 14, then Other number = 27 − 14 = 13 Therefore, the numbers are 13 and 14.
How do you write 13 million in expanded form?
13 million (13,000,000) in expanded form is: (1 x 10000000) + (3 x 1000000) + (0 x 100000) + (0 x 10000) + (0 x 1000) + (0 x 100) + (0 x 10) + (0 x 1)
What is twice the sum of two numbers?
to sum two numbers you add them together then to get twice that you multiply the sum by 2 e.g. if the two numbers are 5 and 8 the sum = 5 + 8 = 13 twice that is 13 x 2 = 26
When will the expression the sum of the squares of two numbers'' and the square of the sum of two numbers'' have the same value?
x2 + y2 = (x + y)2 => x2 + y2 = x2 + 2xy + y2 => 2xy = 0 => xy = 0 So, one of x and y must be 0.
The sum of two quadratic functions will always be quadratic?
No. While the sum of two qudratics cannot have a power greater than two, it could have a power of 2, 1 or 0. x2 + 1 is one quadratic (2-x)(2+x) is another quadratic. Their sum is 1, a constant (power = 0).
What is x in the sum 9x-11-3x-13 equals 0?
First sum the terms with x: 9x + (-3)x = 6 x. Then sum the terms without x: -11 + (-13)x = -24. Then 6x - 24 =0 or x = 24/6 = 4
Find two number whose sum is 27 and product is 182?
Let the first number be x and the second number is 27 − x. [As the sum of both the numbers is 27] Therefore, their product = x (27 − x) It is given that the product of these numbers is 182. x (27 – x) = 182 x2 + 27x - 182 = 0 Changing the signs on both sides we get,x2 - 27x + 182 = 0 Factorizing we get , 13 and 14 are the numbers whose sum is 27 and product is 182 x2 – 13x – 14x + 182 = 0 = x(x – 13) – 14 (x – 13)= 0 = (x – 13) (x – 14) = 0 Either x – 13 = 0 or x − 14 = 0 i.e., x = 13 or x = 14 If first number = 13, then Other number = 27 − 13 = 14 If first number = 14, then Other number = 27 − 14 = 13 Therefore, the numbers are 13 and 14.
The sum of a number x and 13?
x+13 x+13
The sum of the square of a positive number and the square of 5 more than the number is 233 What is the number?
x2 + (x+5)2 = 233 2x2 + 10x + 25 = 233 2x2 + 10x - 208 = 0 2x2 + 26x - 16x - 208 = 0 2x(x+13) - 16(x+13) = 0 (2x-16)(x+13) = 0 So 2x-16 = 0 or x+13=0 So the soln is 2x-16=0 ie x = 8
What is X plus 0 plus 13?
If: x+0 = 13 then x = 13
X2 plus 12x minus 13 equals 0?
x2+12x-13=0 The factor of x2+12x-13 is: (x+13)(x-1) So: x+13 = 0 or x-1 = 0 The answer is: x=-13 or x=1
What is the sum of the roots x2 - 4x - 5 0?
Their sum is 4.
The sum of two numbers is 19 and their product is 78 What is the larger number?
Let x and y be the two numbers. 1) x + y = 19 2) xy = 78 Solve (1) for y. Subtract x from both sides. y = 19 - x Then we can write equation (2) as x(19-x)=78 Simplifying x(19 + -1x) = 78 (19 * x + -1x * x) = 78 (19x + -1x2) = 78 Solving 19x + -1x2 = 78 Solving for variable 'x'. Reorder the terms: -78 + 19x + -1x2 = 78 + -78 Combine like terms: 78 + -78 = 0 -78 + 19x + -1x2 = 0 Factor a trinomial. (-13 + x)(6 + -1x) = 0 == Set the factor '(-13 + x)' equal to zero and attempt to solve: Simplifying -13 + x = 0 Solving -13 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '13' to each side of the equation. -13 + 13 + x = 0 + 13 Combine like terms: -13 + 13 = 0 0 + x = 0 + 13 x = 0 + 13 Combine like terms: 0 + 13 = 13 x = 13 Simplifying x = 13 == Set the factor '(6 + -1x)' equal to zero and attempt to solve: Simplifying 6 + -1x = 0 Solving 6 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-6' to each side of the equation. 6 + -6 + -1x = 0 + -6 Combine like terms: 6 + -6 = 0 0 + -1x = 0 + -6 -1x = 0 + -6 Combine like terms: 0 + -6 = -6 -1x = -6 Divide each side by '-1'. x = 6 Simplifying x = 6 == x = {13, 6} The answer to your question is that the larger number is 13.
The sum of what number and 8 is 0?
Your question is equal to: x + 8 = 0 The answer is x = -8.
What are the two factor numbers with the sum of 20 and the product of 91?
7 and 13. Solution : Let the two numbers be a and b. Then ab = 91 , so b = 91/a. a + b = 20 .......substituting for b, this becomes : a + (91/a) =20 Multiplying both sides by a gives : a2 + 91 = 20a Rearranging : a2 - 20a + 91 = 0 Factoring gives : (a - 7)(a - 13) = 0 Then the numbers occur when x - 7 = 0. → x = 7, and when x - 13 = 0. → x = 13.
What greater absolute -13 or absolute 19?
absolute means the value without the sign: |x| = x if x ≥ 0 |x| = -x if x < 0 →|-13| = 13 →|19| = 19 19 > 13 → |19| > |-13|
What are three consecutive integers whose sum is 42?
13, 14, 15 13 + 14 + 15 = 42 Solution: Let the numbers be x, x+1 and x+2. So their sum is 3x+3 which is said to be 42. Hence x = 13
