3 and 10
The sum of 3 and 10 is 13
The difference of 3 and 10 is 7
Using algebraic notation, if the two numbers are x and y:
x + y = 13
x - y = 7
If you add these two equations you get
2x = 20 so x = 10
Substituting this back into the original equations you find that y must then be 3
it has to be 2 numbers not just 1, duh stupid
6
5
8 and 6 have a difference of 2 and a sum of 14.
to sum two numbers you add them together then to get twice that you multiply the sum by 2 e.g. if the two numbers are 5 and 8 the sum = 5 + 8 = 13 twice that is 13 x 2 = 26
60
2, 3, and 13 are all prime numbers and their sum is equal to 18.
Let's name the first number x and the next number x + 1. So, x^2 - (x + 1)^2 = x^2 - (x^2 + 2x + 1) = x^2 - x^2 - 2x - 1 = - 2x - 1 = -(2x + 1) Thus we can say that, the difference between the squares of two consecutive numbers is equal to the opposite of their sum (means it is their sum, but as a negative number). Let's do some examples: 2, 3; 2 + 3 = 5 2^2 - 3^2 = 4 - 9 = -5 ( 5 and -5 are opposite numbers, and 5 is the sum of 2 and 3) 13, 14; 13 + 14 = 27 13^2 - 14^2 = 169 - 196 = -27 (27 and -27 are opposite numbers, and 27 is the sum of 13 and 14)
9 13
32 and 19
The numbers are 7 and 6
9 + 13 = 22
The two numbers are 13 and 8
The difference of 2 numbers is 32 the sum is 158 what are the 2 numbers?
9+13=22 13-9=4
We are looking for 2 numbers.The product is 36 = 4 x 9The sum is 13 = 4 + 9State the numbers: 4, 9Their difference: 9 - 4 = 5
13 and 8 13 + 8 = 21 13 - 8 = 5
5 and 8
8 and 6 have a difference of 2 and a sum of 14.
It's not possible. For two numbers to have a sum of 13, one would have to be even, that is, divisible by 2.