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The sum of two numbers witha difference of two equals forty can be set up and solved this way: x + (x - 2) = 40 2x - 2 = 40 2x = 42 x = 21 x - 2 = 19 The two numbers are 21 and 19.
Four consecutive odd integers: [2x-1], [2x+1], [2x+3], [2x+5].Their sum: (2x-1) + (2x+1) + (2x+3) + (2x+5) = 8x + 8 = 8(x+1) = 28,458,968(x+1) = 28,458,968/8 = 3,557,371x = 3,557,370The numbers are:7,114,739=> 7,114,741
(2x-1) + (2x+1) + (2x+3) = 1172x - 1 + 2x + 1 + 2x + 3 = 1176x + 3 = 1176x = 114x = 19The numbers are 37, 39, and 41.
Twice the sum of 'x' and 'y' . . . 2(x+y) The sum of twice 'x' and 'y' . . . (2x+y)
If: 7x = 70 Then: x = 10