The sum of two numbers witha difference of two equals forty can be set up and solved this way: x + (x - 2) = 40 2x - 2 = 40 2x = 42 x = 21 x - 2 = 19 The two numbers are 21 and 19.
Four consecutive odd integers: [2x-1], [2x+1], [2x+3], [2x+5].Their sum: (2x-1) + (2x+1) + (2x+3) + (2x+5) = 8x + 8 = 8(x+1) = 28,458,968(x+1) = 28,458,968/8 = 3,557,371x = 3,557,370The numbers are:7,114,739=> 7,114,741
(2x-1) + (2x+1) + (2x+3) = 1172x - 1 + 2x + 1 + 2x + 3 = 1176x + 3 = 1176x = 114x = 19The numbers are 37, 39, and 41.
Twice the sum of 'x' and 'y' . . . 2(x+y) The sum of twice 'x' and 'y' . . . (2x+y)
If: 7x = 70 Then: x = 10
What is The Sum for -2x And 8
2(x+y) is twice the sum of x and y, and 2x+y is the sum of twice x and y
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The sum of two numbers witha difference of two equals forty can be set up and solved this way: x + (x - 2) = 40 2x - 2 = 40 2x = 42 x = 21 x - 2 = 19 The two numbers are 21 and 19.
Suppose x is the larger number Then the smaller number is x - 26 Their sum is x + (x - 26) which is 102 So 2x - 26 = 102 or 2x = 128 so that x = 64
Four consecutive odd integers: [2x-1], [2x+1], [2x+3], [2x+5].Their sum: (2x-1) + (2x+1) + (2x+3) + (2x+5) = 8x + 8 = 8(x+1) = 28,458,968(x+1) = 28,458,968/8 = 3,557,371x = 3,557,370The numbers are:7,114,739=> 7,114,741
Suppose one of the numbers is x. Then, because they sum to 82, the other number is 82 - x. Then their difference gives the equation x - (82 - x) = 24 or 2x - 82 = 24
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Zero. The sum of anything and it's opposite is zero, that's how an opposite is defined. In this case, the opposite of 2x + 1 is -(2x + 1) = -2x - 1 by the distributive property. Adding like terms, 2x + -2x + 1 +-1 = 0 + 0 = 0.
3[(x^2) + 5] x (2x-y) Do the parentheses first, then brackets next. P.e.m.d.a.s.
-2x+2x