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5-2x3 5-6 -1
Answer this question…A. x4 + 2x3 + 9x2 + 4 B. x4 + 4x3 + 9x2 + 4 C. x4 + 2x3 + 9x2 + 4x + 4 D. x4 + 2x3 + 9x2 - 4x + 4
product - 5 factor x factor = product (factor x factor) - 5 you need to state what the product were. If, for example, the factors were 2 and 3, then your answer would turn out like this: your product will be: 2x3= 6 and then substract 5 6 - 5 = 1 like this: 2x3 - 5 = 1
2X3 2 + 2 + 2 = 6 3 + 3 = 6 ^ thats how ^
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5-2x3 5-6 -1
2x3=6+4=10 2.
Answer this question…A. x4 + 2x3 + 9x2 + 4 B. x4 + 4x3 + 9x2 + 4 C. x4 + 2x3 + 9x2 + 4x + 4 D. x4 + 2x3 + 9x2 - 4x + 4
10
product - 5 factor x factor = product (factor x factor) - 5 you need to state what the product were. If, for example, the factors were 2 and 3, then your answer would turn out like this: your product will be: 2x3= 6 and then substract 5 6 - 5 = 1 like this: 2x3 - 5 = 1
2X3 2 + 2 + 2 = 6 3 + 3 = 6 ^ thats how ^
(2x3)+(3x5)-(3x2)= 2x3=6 3x5=15 3x2=6 So..... 6x25-6= 6x25=150 150+6=156
your equation is this... 2x3 + 11x = 6x 2x3 + 5x = 0 x(2x2 + 5) = 0 x = 0 and (5/2)i and -(5/2)i
f'(x) = 1/(2x3 + 5) rewrite f'(x) = (2X3 + 5) -1 use the chain rule d/dx (2x3 + 5) - 1 -1 * (2x3 + 5)-2 * 6x2 - 6x2(2x3 + 5) -2 ==================I would leave like this rather than rewriting this
False
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