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How do you factor out 3x2-3y2?
(sqrt(3)x-sqrt(3)y)(sqrt(3)x+sqrt(3)y)
What is the value of x in the equation x y 30 when y 15?
If you mean: x+y = 30 and the value of y is 15 then the value of x is also 15
What is the tangent equation for 2x3-3x2-8x plus 9 when x equals 2?
The tangent to 2x3 - 3x2 - 8x + 9 at x = 2 is y = 4x - 11 The tangent to y = 2x3 - 3x2 - 8x + 9 at x = 2 has the same gradient as the curve at that point; to find the gradient, differentiate: dy/dx = 6x2 - 6x - 8 which at x = 2 is: gradient = 6 x 22 - 6 x 2 - 8 = 4 At x = 2, y = 2 x 23 - 3 x 22 - 8 x 2 + 9 = -3 The equation of a line through point (xo, yo) with gradient m is: y - yo = m(x - xo) Thus the equation of the tangent to the line at x = 2 is: y - -3 = 4(x - 2) ⇒ y = 4x - 11
What is an expression for subtract 16?
Y = X - 16 X= Y + 16 X is the original value. Y is the new value of the original value - 16.
If y varies directly as x and y 36 x 9 then what is the value of x when y 12?
If y varies directly as x and y is 36 when x is 9, then y is always four times the value of x. So if y is 12, then x is 3.
What is the value of x in this equation y equals 3x2?
x = +/- sqrt(y/3)
What is the value of x in the equation y 3x2 6x - 12?
The value of x is 2
Find the value for x if 36÷3-(3x2=y)?
72
When you completely factor 3x2 y what do you get?
3 * x * x * y
3x2 - y 6?
3x2-y=6 3x2-y=6
What is the Factor 3x2 plus 6xy plus 3y2?
(3x + 3y)(x + y) or 3(x + y)2
How do you factor out 3x2-3y2?
(sqrt(3)x-sqrt(3)y)(sqrt(3)x+sqrt(3)y)
What is the x-coordinate of the vertex of the parabola whose equation is y 3x2 9x?
Without an equality sign it can not be considered to be an equation and the - or + value of 9x has not been given
What does x - y?
In expressions such as "x-y", both "x" and "y" can have any value. The value of "x-y" will depend on what the value of "x" and the value of "y" are.
What is the x-coordinate of the of the vertex of y equals -3x2 plus 12x-5?
You can find the x-coordinate of it's vertex by taking it's derivative and solving for zero: y = -3x2 + 12x - 5 y' = -6x + 12 0 = -6x + 12 6x = 12 x = 2 Now that we have it's x coordinate, we can plug it back into the original equation to find it's y coordinate: y = -3x2 + 12x - 5 y = -3(2)2 + 12(2) + 5 y = -12 + 24 + 5 y = 17 So the vertex of the parabola y = -3x2 + 12x - 5 occurs at the point (2, 17).
What is the value of 3x2 - y2 if x equals -1 and y equals 3?
x = -1y = 33x2 - y2 = 3 (-1)2 - (3)2 = 3 (1) - 9 = -6
3xsquare-2ysquare equals 9xsquare plus 4ysquare-12xy how do you reach this answer?
3x2 - 2y2 = 9x2 + 4y2 - 12xy (subtract 3x2 and add 2y2 to both sides) 0 = 9x2 -3x2 + 4y2 + 2y2 - 12xy 0 = 6x2 + 6y2 - 12xy (divide by 6 to both sides) 0 = x2 + y2 - 12xy or x2 - 2xy + y2 = 0 (x - y)(x - y) = 0 x - y = 0 x = y
