y = 3x - 2
3x = y + 2
x = y + 2
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3
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(sqrt(3)x-sqrt(3)y)(sqrt(3)x+sqrt(3)y)
If you mean: x+y = 30 and the value of y is 15 then the value of x is also 15
Y = X - 16 X= Y + 16 X is the original value. Y is the new value of the original value - 16.
The tangent to 2x3 - 3x2 - 8x + 9 at x = 2 is y = 4x - 11 The tangent to y = 2x3 - 3x2 - 8x + 9 at x = 2 has the same gradient as the curve at that point; to find the gradient, differentiate: dy/dx = 6x2 - 6x - 8 which at x = 2 is: gradient = 6 x 22 - 6 x 2 - 8 = 4 At x = 2, y = 2 x 23 - 3 x 22 - 8 x 2 + 9 = -3 The equation of a line through point (xo, yo) with gradient m is: y - yo = m(x - xo) Thus the equation of the tangent to the line at x = 2 is: y - -3 = 4(x - 2) ⇒ y = 4x - 11
If y varies directly as x and y is 36 when x is 9, then y is always four times the value of x. So if y is 12, then x is 3.