-8
If you mean: y = -3x then the slope of the line is -3
If you mean: 3x-y=5 then y=3x-5 and the perpendicular equation is y=-1/3x-7
y=3x
If you mean y = -3x-4 then it is the function of a straight line equation
y = 3x-1 The y intercept is -1 y = 3x-11 The y intercept is -11
-11
3x + y = 4 y = -3x + 4 (the slope is -3) The line that passes through the point (-3, -2) has a slope of -3, since it is parallel to the line with equation 3x + y = 4 (parallel lines have equal slopes). Using the slpoe -3 and the point (-3, -2) we find the equation of the required line such as (y - -2) = -3(x - -3) y + 2 = -3x - 9 y = -3x -11 3x + y = -11
y = 1.5x. y intercept = 0.
-8
Your answer can be solved by rewriting the equation in point-intercept notation. * -3x + 2y = 11 * 2y = 3x + 11 * y = (3x+11)/2 That line lists all of the possible answers.
Straight line: 3x-y = 5 Curved parabola: 2x^2 +y^2 = 129 Points of intersection works out as: (52/11, 101/11) and (-2, -11)
It works out that line 3x-y = 5 makes contact with the curve 2x^2 +y^2 = 129 at (52/11, 101/11) and (-2, -11)
-4
-3
If you mean: y = -3x then the slope of the line is -3
Slope=3, y-intercept=0. y=3x or y=3x+0