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If you mean y = 3x-11 then the slope is 3 and the y intercept is -11

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Q: What is the y interceptof line y 3x -11?
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What is the y-intercept of the line y equals 3x -1?

y = 3x-1 The y intercept is -1 y = 3x-11 The y intercept is -11


What is the y-coordinate of the y-intercept of the line given by the equation y equals 3x - 11?

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Find the equation of the line through the point -3-2 and Parallel to the line 3x plus y equals 4?

3x + y = 4 y = -3x + 4 (the slope is -3) The line that passes through the point (-3, -2) has a slope of -3, since it is parallel to the line with equation 3x + y = 4 (parallel lines have equal slopes). Using the slpoe -3 and the point (-3, -2) we find the equation of the required line such as (y - -2) = -3(x - -3) y + 2 = -3x - 9 y = -3x -11 3x + y = -11


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y = 1.5x. y intercept = 0.


What is the y-intercept of the line given by the equation y 3x - 11?

-8


-3x plus 2y equals 11?

Your answer can be solved by rewriting the equation in point-intercept notation. * -3x + 2y = 11 * 2y = 3x + 11 * y = (3x+11)/2 That line lists all of the possible answers.


What are points of intersection of the line 3x -y equals 5 with the curve of 2x squared plus y squared equals 129?

Straight line: 3x-y = 5 Curved parabola: 2x^2 +y^2 = 129 Points of intersection works out as: (52/11, 101/11) and (-2, -11)


Where are the points of contact when the line 3x -y equals 5 passes through the curve 2x squared plus y squared equals 129?

It works out that line 3x-y = 5 makes contact with the curve 2x^2 +y^2 = 129 at (52/11, 101/11) and (-2, -11)


which line is perpendicular to y= -1/3x?

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What is the slope of the line y equals 3x?

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