y = 3x-1
The y intercept is -1
y = 3x-11
The y intercept is -11
3x - 4y = 10-3x - 4y = 8 -> add line 1 to line 2 3x - 4y = 100x - 8y = 18 -> -8y = 18 -> y = -18/8 = -9/4 -> 3x - 4*(-9/4) = 10 -> 3x + 9 = 10 -> 3x = 1 -> x = 1/3
y = 1/3x+4
-1
- 1/3
Algebraically rearrange both lines to ' y = ''' Hence y = 3x & 3y = x => y = (1/3)x Since the two lines are now y = 3x & y = (1/3)x The lines y = 3x has the greater/steeper slope at '3' , Whereas the other line has a slope of ' 1/3 '. (much less steep).
3x - 4y = 10-3x - 4y = 8 -> add line 1 to line 2 3x - 4y = 100x - 8y = 18 -> -8y = 18 -> y = -18/8 = -9/4 -> 3x - 4*(-9/4) = 10 -> 3x + 9 = 10 -> 3x = 1 -> x = 1/3
y = 1/3x+4
3/4
3/1
-3
3x+y = 4 y = -3x+4 Perpendicular slope: 1/3
-1
- 1/3
Equation of given line: 3x + y = 15 or y = -3x + 15 Slope of given line = coefficient of x = -3 Slope of perperndicular = -1/(slope of given line) = -1 / (-3) = 1/3
y = 1/3x+4/3
-4
y-6=3x-5 y=3x+1 (0,1)(1,4)(2,7)etc