-8
y-intercept = -11
y-intercept; x=0
substitute x = 0 i
n the equatio
n y = 3x -11
y = 3x - 11
y = 3(0) - 11
y = 0 -11
y = -11
It is an equation of a straight line.
it should actually look like this- 5x - y = 11 sorry
Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.
Points: (7, 0) and (0, 11) Slope: 0-11/7-0 = -11/7 Equation: y-0 = -11/7(x-7) => 7y = -11x+77 Equation: y-11 = -11/7(x-0) => 7y = -11x+77
Points: (1, 11) and (-2, 2) Slope: (11-2)/(1--2) = 3 Equation: y-11 = 3(x-1) => y = 3x+8 Equation: y-2 = 3(x--2) => y = 3x+8
11
-11
11
Without an equality sign the given expression can't be considered to be a straight line equation.
(-2, 11)(-3, 14)(2, -1)
If you mean y = 11x+2.5 then the slope is 11 and the y intercept is 2.5
y = 11x + 5 The slope/gradient of this equation is 11. The slope/gradient can easily been seen in a linear equation: it is simply the co-efficient of x
It is an equation of a straight line.
The equation of a parallel line is of the form 2x - y = c for some c. (-3, -11) is on this lime so 2*(-3) - (-11) = c -6 + 11 = c so that c = 5 and therefore, the equation is 2x - y = 5
Given points: (6, 11), (3, 10)Find: the equation of the line that passes through the given points Solution: First, wee need to find the slope m of the line, and then we can use one of the given points in the point-slope form of the equation of a line. After that you can transform it into the general form of the equation of a line. Let (x1, y1) = (3, 10), and (x2, y2) = (6, 11) slope = m = (y2 - y1)/(x2 - x1) = (11 - 10)/(6 - 3) = 1/3 (y - y1) = m(x - x1)y - 10 = (1/3)(x - 3)y - 10 = (1/3)x - 1y - 10 + 10 - (1/3)x = (1/3)x - (1/3)x + 10 - 1-(1/3)x + y = 9 which is the general form of the required line.
it should actually look like this- 5x - y = 11 sorry
Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.