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What is x5 divided by x3?
1.6667
2x3 - 7 plus 5x2 - x3 plus 3x - x3?
2x3 - 7 + 5x - x3 + 3x - x3 = 8x - 7
What is x cubed minus 4 x squared plus 7 x divided by x equals?
[ x3 - 4x2 + 7x ] / (x) = x2 - 4x + 7
What is x divided by 3?
x/3
What is the derivative of ln x divided by x cubed?
I will use the quotient rule here. d/dx(f(x)/g(x) = g(x)*f'(x) - f(x)*g'(x)/[g(x)]2 x3*1/x - ln(x)*3x2/(x3)2 x3/x - 3ln(x)x2/x6 x2 - 3ln(x)x2/x6 = - 3ln(x)/x4 =========
What is x5 divided by x3?
1.6667
What is the inverse of x3 plus 1?
The inverse of a number is 1 divided by that number. So the inverse of x3 + 1 is 1/(x3 + 1).
What is the answer to x4 plus x3 minus 14x2 plus 4x plus 6 divided by x minus 3?
The answer to x4+x3-14x2+4x+6 divided by x-3 is x3+4x2-2x-2
What is the derivative of 1 divided by x3?
0.3333
What is -x3 plus 75x-250 divided by x plus 10?
(-x3 + 75x - 250) / (x + 10) = x2 - 10x - 25
What is x3 plus x plus 1 divided by x-1?
4
How can you demonstrate that the function x3 is in the set o(x4)?
To demonstrate that the function x3 is in the set o(x4), you can show that the limit of x3 divided by x4 as x approaches infinity is equal to 0. This indicates that x3 grows slower than x4, making it a member of the set o(x4).
The indefinite integral of x2 divided by 4 plus 16?
x3 /12 + 16x + c
What is 6X3 divided by 12X simplified?
6x3/12x = 6/12 * x3/x = 0.5*x2
What is X3 plus X2 plus X plus 1 divided by X 1?
2x2+7/x1
What is the quotient and remainder if any when the expession 4x4 -x3 plus 17x2 plus 11x plus 4 is divided by 4x plus 3?
Dividend: 4x4-x3+17x2+11x+4 Divisor: 4x+3 Quotient: x3-x2+5x-1 Remainder: 7
What is x3 plus 4x2-3x-12 divided by x2-3?
(x3 + 4x2 - 3x - 12)/(x2 - 3) = x + 4(multiply x2 - 3 by x, and subtract the product from the dividend)1. x(x2 - 3) = x3 - 3x = x3 + 0x2 - 3x2. (x3 + 4x2 - 3x - 12) - (x3 + 0x2 - 3x) = x3 + 4x2 - 3x - 12 - x3 + 3x = 4x2 - 12(multiply x2 - 3 by 4, and subtract the product from 4x2 - 12)1. 4x(x - 3) = 4x2 - 12 = 4x2 - 122. (4x2 - 12) - (4x2 - 12) = 4x2 - 12 - 4x2 + 12 = 0(remainder)
