1.6667
The inverse of a number is 1 divided by that number. So the inverse of x3 + 1 is 1/(x3 + 1).
The answer to x4+x3-14x2+4x+6 divided by x-3 is x3+4x2-2x-2
0.3333
(-x3 + 75x - 250) / (x + 10) = x2 - 10x - 25
4
To demonstrate that the function x3 is in the set o(x4), you can show that the limit of x3 divided by x4 as x approaches infinity is equal to 0. This indicates that x3 grows slower than x4, making it a member of the set o(x4).
x3/x1/2 = x5/2.
x3 /12 + 16x + c
6x3/12x = 6/12 * x3/x = 0.5*x2
Dividend: 4x4-x3+17x2+11x+4 Divisor: 4x+3 Quotient: x3-x2+5x-1 Remainder: 7
2x2+7/x1