We know that a logarithm is an exponent. Let x^8 = a. For x > 0, x is different than 1, and a > 0, x^8 = a is equal to the log with base x of a = 8
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(x-8)(x+8)
(x - 3)(x + 8)
I is -8x^2.
x^2-4x/x^2-6x+8 = x(x-4)/(x-2)(x-4) = x/(x-2)
Well, darling, when you divide x to the power of 8 by x squared, you subtract the exponents. So, x to the power of 8 divided by x squared is x to the power of 8 minus 2, which simplifies to x to the power of 6. So, there you have it, x to the power of 6 is the sassy answer you're looking for.