y=x2-18x+52
First off, this does not factor cleanly, but even if it did it would not help us. We must complete the square to yield a perfect-square trinomial (a trinomial that can be written in the form (x-a)2 where a is a real number.
To do this, halve the coefficient of the single-x term (for this case, the term 18x) and square it.
18/2=9
92=81
The result of this process can be added to the two terms involving x to get a perfect square trinomial. For instance, the trinomial that would result would be:
x2-18x+81=(x-9)2
However, there is already 52 of that 81 that is needed present, so in reality, you only need to add 29 (81-52=29) to the right side of the equation to get a perfect-square trinomial. Whatever is done to one side of the equation must be done to the other side, so since you added 29 to the right side, you must add 29 to the left side, giving you:
y+29=x2-18x+52+29
y+29=x2-18x+81
y+29=(x-9)2
y=(x-9)2-29
This is in vertex form, you can see that the vertex is at (9,-29)
The vertex form is y = (x - 4)2 + 13
The standard form of the quadratic function in (x - b)2 + c, has a vertex of (b, c). Thus, b is the units shifted to the right of the y-axis, and c is the units shifted above the x-axis.
The vertex form of this function.X2 + 22X = 31Halve the linear term ( 22 ) square it and add it to both sides.X2 + 22X + 121 = 31 + 121Factor the left side of this equation and gather terms on the right side.(X + 11)2 = 152(X + 11)2 - 152 = 0===================vertex form of this function(- 11, - 152 )===========Vertex
Interpreting that function as y=x2+2x+1, the graph of this function would be a parabola that opens upward. It would be equivalent to y=(x+1)2. Its vertex would be at (-1,0) and this vertex would be the parabola's only zero.
Take the derivative: y' = 2x + 4. Set equal to zero: 2x + 4 = 0 --> x = -2. Substitute into original and y = -3. Axis of symmetry is x = -2. Vertex is (-2,-3)
The vertex of the positive parabola turns at point (-2, -11)
The vertex is at (-1,0).
The vertex has a minimum value of (-4, -11)
The equation is linear and so has no vertex.
The given equation is y = x - 4x + 2 which can be written as y = -3x + 2 This is an equation of a straight line. Therefore it has no vertex and so cannot be written in vertex form.
The vertex is at the point (0, 4).
The vertex form is y = (x - 4)2 + 13
-2-5
y = x +1 is the equation of a straight line and so has no vertex.
factors are (x + 9)(x - 4) so x = 4 or -9. Does that help?
(3, -21)
x = -3y = -14