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How do you find the vertex of the parabola y equals -4x2 - 16x - 11?
You would convert it to vertex form by completing the square. You can also find the optimum value as optimum value and vertex are the same.
Find the vertex of y equals x2 plus 10x plus 22?
-2-5
How do you construct an isosceles triangle when base and angle at the vertex is given?
First find 180 minus the vertex angle and divide that by 2 to get the other angles. Then solve the other sides by using sin(vertex angle)/base=sin(other angles)/other sides.
how to find the vertex angle?
The vertex angle is connected to the vertex point
Find dyoverdx by implicit differentiation xy2 minus x2y equals 3xy?
Whooop!
How do you find the vertex of the parabola y equals -4x2 - 16x - 11?
You would convert it to vertex form by completing the square. You can also find the optimum value as optimum value and vertex are the same.
Find the vertex of y equals x2 plus 10x plus 22?
-2-5
Find the vertex and equation of the directri for y2 equals -32x?
y2 = 32x y = ±√32x the vertex is (0, 0) and the axis of symmetry is x-axis or y = 0
How do you construct an isosceles triangle when base and angle at the vertex is given?
First find 180 minus the vertex angle and divide that by 2 to get the other angles. Then solve the other sides by using sin(vertex angle)/base=sin(other angles)/other sides.
how to find the vertex angle?
The vertex angle is connected to the vertex point
Find dyoverdx by implicit differentiation xy2 minus x2y equals 3xy?
Whooop!
In an isosceles triangle one base angle equals 73 find the size of the vertex angle?
jaj no se kompas jaj
How do you solve 3 plus 5 equals x-7?
you do 3 plus 5 first then you get 8 you have to find out what minus 7 equals 8
Where could i find a vertex?
You can find a vertex wherever two lines (or line segments) meet.
How do you find the x intercepts using the vertex and y intercept?
It depends on the vertex of what!
What is the vertex of the parabola y-2x2-4x 4?
Assuming the missing symbol there is an equals sign, then we have: y - 2x2 - 4x = 4 We can find it's vertex very easily by solving for y, and finding where it's derivative equals zero: y = 2x2 + 4x + 4 y' = 4x + 4 0 = 4x + 4 x = -1 So the vertex occurs Where x = -1. Now we can plug that back into the original equation to find y: y = 2x2 + 4x + 4 y = 2 - 4 + 4 y = 2 So the vertex is at the point (-1, 2)
6-s when s equals -8?
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