The three consecutive numbers whose sum is 294 are 96, 98 and 100. Also, 97, 98 and 99.
301
The numbers are 9, 10 and 11.
The three numbers that can be multiplied to get 48 are 4, 4, and 3. This is because 4 x 4 x 3 = 48. These numbers are the factors of 48, which are numbers that can be multiplied together to get the original number. In this case, 4, 4, and 3 are the factors of 48 that multiply to give the original number.
You should multiply the numbers, but add the exponents. For example: 92 x 27 = 189
Oh, dude, you're hitting me with the math questions, huh? Alright, so to find numbers that multiply to 294, we can break it down like a boss. 294 can be written as 2 x 3 x 7 x 7. So, the numbers that multiply to 294 are 2, 3, 7, and 7. Voilà!
301
There are no two real numbers that do, but two complex numbers do: (3.5 + i 3.5 √23) and (3.5 - i 3.5 √23) If you want them to add to 7 and multiply to -294, then the two real numbers -14 and 21 work. Or if you want them to add to -7 and multiply to -294, then the two real numbers 14 and -21 work. To add to -7 and multiply to 294, the following two complex numbers work: (-3.5 + i 3.5 √23) and (-3.5 - i 3.5 √23)
The three consecutive numbers whose sum is 294 are 96, 98 and 100. Also, 97, 98 and 99.
The prime factorization of 294 is 2 * 3 * 7 * 7. Therefore, the four prime numbers that multiply to make 294 are 2, 3, 7, and 7.
297
1,294 2,147 3,98 6,49 7,42 14,21
The numbers are: 11+ square root of 415 and 11 - square root of 415
As a product of its prime factors: 2*3*7*7 = 294
There are multiple pairs of numbers that will multiply to make 294.1 x 2942 x 1473 x 986 x 497 x 4214 x 21
x +y = 7 xy = -294 y = 7-x x(7-x) = -294 7x - x2 +294 = 0 x2 - 7x -294 = 0 (x-21)(X+14) = 0 x = 21 Y = -14
6*7*7 = 294