As a product of its prime factors: 2*3*7*7 = 294
294 = 2 x 3 x 7 x 7
No because they are both composite numbers
You can multiply to numbers with decimals
If you allow fractions and decimals, then there are an infinite quantity of numbers that "go into" 294.If we restrict the search to positive whole numbers, then we're looking for the "factors" of 294.They are: 1, 2, 3, 6, 7, 42, 49, 98, 147, and 294
73.5*2*2=294
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There are no two real numbers that do, but two complex numbers do: (3.5 + i 3.5 √23) and (3.5 - i 3.5 √23) If you want them to add to 7 and multiply to -294, then the two real numbers -14 and 21 work. Or if you want them to add to -7 and multiply to -294, then the two real numbers 14 and -21 work. To add to -7 and multiply to 294, the following two complex numbers work: (-3.5 + i 3.5 √23) and (-3.5 - i 3.5 √23)
The prime factorization of 294 is 2 * 3 * 7 * 7. Therefore, the four prime numbers that multiply to make 294 are 2, 3, 7, and 7.
1,294 2,147 3,98 6,49 7,42 14,21
The numbers are: 11+ square root of 415 and 11 - square root of 415
As a product of its prime factors: 2*3*7*7 = 294
There are multiple pairs of numbers that will multiply to make 294.1 x 2942 x 1473 x 986 x 497 x 4214 x 21
x +y = 7 xy = -294 y = 7-x x(7-x) = -294 7x - x2 +294 = 0 x2 - 7x -294 = 0 (x-21)(X+14) = 0 x = 21 Y = -14
Prime decomposition of 294: 294 = 2 x 3 x 7^2 Other ways of writing 294: 294 = 1 x 294 294 = 2 x 147 294 = 3 x 98 294 = 6 x 49 294 = 7 x 42 294 = 14 x 21
96+98+100 = 294
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