Let the integers be 'm' & 'm+`1'.
Hence
m + m+ 1 = 57
2m + 1 = 57
2m = 56
m = 28
M+ 1 = 28 + 1 = 29
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57 and 58.
The numbers are 51, 53, 55 and 57.
The numbers are 55, 56 and 57 OR 54, 56 and 58
x+(x+2)+(x+4)+(x+6)=2164x+12=2164x=204x=51the integers are 51, 53, 55, and 57
the only two odd numbers are 57 and 59 which give a sum of 116