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Any pair of numbers where the 'y' is 5 more than the 'x'. There are an infinite number of suitable pairs. 2y-2x=10 2y-2x+2x=10+2x 2y=2x+10 divide both side by 2. y=x+5
If: 12 = 2y+x then y = -1/2x+6 So: y = 2x+4 and y = -1/2x+6 which means that they are perpendicular lines
They are parallel lines.
2y = -10y = -58 - 2x - 2(-5) = -108 - 2x + 10 = -10-2x = -10 - 182x = 28x = 14Check:2y = 8 - 2x - 2y = -102(-5) = 8 - 2(14) - 2(-5) = -10-10 = 8 - 28 + 10 = -10-10 = -20 + 10 = -10-10 = -10 = -10
x + 2y = 7 2y = -x + 7 y = -(x-7)/2 => -x/2 + 7/2 2x - y = 7 -y = -2x + 7 y = 2x + 7 Since -1/2 is the negative reciporical of 2, the slopes of these equations are perpendicular. Therefore, these two lines are perpendicular.
parallel
Any pair of numbers where the 'y' is 5 more than the 'x'. There are an infinite number of suitable pairs. 2y-2x=10 2y-2x+2x=10+2x 2y=2x+10 divide both side by 2. y=x+5
perpendicular JEW
If: 12 = 2y+x then y = -1/2x+6 So: y = 2x+4 and y = -1/2x+6 which means that they are perpendicular lines
They are parallel lines.
They are straight lines.
2y = -10y = -58 - 2x - 2(-5) = -108 - 2x + 10 = -10-2x = -10 - 182x = 28x = 14Check:2y = 8 - 2x - 2y = -102(-5) = 8 - 2(14) - 2(-5) = -10-10 = 8 - 28 + 10 = -10-10 = -20 + 10 = -10-10 = -10 = -10
If you mean 3x+2y = -5 and -2x+3y = -5 then they are straight line equations
If you mean: y = 2x and 2y = -x+4 then they are positive and negative straight line equations
To determine the type of lines represented by the equations ( y = 2x + 4 ) and ( y = 2x + 5 ), we can observe their slopes. Both equations have the same slope of 2, indicating that they are parallel lines. Since parallel lines never intersect, they will never meet at any point on the graph.
x + 2y = 7 2y = -x + 7 y = -(x-7)/2 => -x/2 + 7/2 2x - y = 7 -y = -2x + 7 y = 2x + 7 Since -1/2 is the negative reciporical of 2, the slopes of these equations are perpendicular. Therefore, these two lines are perpendicular.
6x-2x-6xy-2x-2y4x-2y=2x-2y-14xy