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3x^2 - x + 20 = 0 doesn't factor neatly. Using the quadratic formula, we find two complex roots with imaginary solutions.

(1 plus the square root of -239) divided by 6

(1 minus the square root of -239) divided by 6

x = 0.16666 repeating + 2.576604138956718i

x = 0.16666 repeating - 2.576604138956718i

where i is the square root of negative one.

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9y ago
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9y ago

Unfortunately, the browser used by Answers.com for posting questions is incapable of accepting mathematical symbols. This means that we cannot see the mathematically critical parts of the question. We are, therefore unable to determine what exactly the question is about and so cannot give a proper answer to your question. Please edit your question to include words for symbols and resubmit. There is no equality symbol in the question, so there is no equation!

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9y ago

I assume you mean either 3x2 -x + 20 = 0, or 3x2 -x - 20 = 0. Use the quadratic formula, replacing a = 3, b = -1, and c = 20 (or -20).

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Q: What are the roots of the equation 3X2-X 20?
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