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What is the median of 97 85 92 and 86?
The idea is to sort the numbers, and pick the number in the middle as the median. In cases like this, when you have two numbers in the middle (the size of the set is even), take the average of those two numbers.
What is the mean median and mode for the following numbers 87 75 89 81 90 73 85 96 65 92 78 79 83 85 79 90 86 72 74 88 81 85?
meanAdd up the numbers and divide by how many there are: 87+75+89+81+90+73+85+96+65+92+78+79+83+85+79+90+86+72+74+88+81+85 = 1813There are 22 numbers.⇒ mean = 1813 ÷ 22= 829/22≈ 82.41medianSort the numbers into order; the median is the middle number (if an odd number of numbers) or the mean of the middle two (if an even number of numbers): Sorted: 65, 72, 73, 74, 75, 78, 79, 79, 81, 81, 83, 85, 85, 85, 86, 87, 88, 89, 90, 90, 92, 96There are 22, so the median is the mean of the middle two which are the 11th (83) and 12th (85) numbers:⇒ median = (83+85) ÷2= 84modeThe number which appears the most often. Having sorted the list for the median, it can be seen that the one with the highest frequency appears three times: ⇒ mode = 85
What is the median of 85 93 95 96 98 99 100 100?
The median for 85, 93, 95, 96, 98, 99, 100, 100 is 97. The number in the middle is 96, and 98. Add - 96 + 98 = 194 Divide - 194 ÷ 2 = 97
The average of 4 numbers is 85 in the numbers 76 78 and 81 what number would come next?
Let denote the missing number with x. So we have:(76 + 78 + 81 + x)/4 = 85(235 + x)/4 = 85(4)(235 + x)/4 = (4)(85)235 + x = 340235 - 235 + x = 340 - 235x = 105
The sum of the squares of two consecutive positive numbers is 85?
Let the numbers be m & m+1 (consecutive) Hence their squares are m^2 & ( m + 1)^2 => m^2 & m^2 + 2m + 2 Hence Their sum is m^2 + m^2 + 2m + 1 = 85 2m^2 + 2m - 84 = 0 m^2 + m - 42 =0 Factor (m + 7)(m - 6) = 0 Hence the numbers are 6 & 7 .
What is the median if the numbers are 99 87 85 32 57 82 85 99 85 65 78 87 85 57 85 99?
The median is 85.
What is the mean median mode range of 89 76 85 76 77 84?
For median the list needs to be sorted into increasing order, but doing so also helps with the range and mode, so I'll do that first: {89, 76, 85, 76, 77, 84} → {76, 76, 77, 84, 85, 89} Mean: add them up and divide the sum by how many numbers there are: mean = (89 + 76 + 85 + 76 + 77 + 84) / 6 = 81 1/6 ≈ 81.167 Median: middle number when listed in order; if there are an even number of data items, then the median is the mean average of the middle two: There are 6 data items so median is mean average of middle two: median = (77 + 84) / 2 = 80 ½ = 80.5 Mode: the most frequent, it the number which occurs the most often. There can be more than one mode: mode = 76 as there are two of them and only 1 of all the other numbers. Range: the difference between the greatest and least numbers: range = 89 - 76 = 13
What is the median for 84 83 82 87 68 74 91 95 98 88 74 66 85 100 91 62 93 91?
The median is the average of 85 and 87, that is 86.The median is the average of 85 and 87, that is 86.The median is the average of 85 and 87, that is 86.The median is the average of 85 and 87, that is 86.
How do you find the average for the following group of numbers 85 92 84 85 96 95?
add them all up and divide by how many numbers there are so..... 85+92+84+85+96+95=? and divide by 6
What is the median for the numbers 99 87 32 57 82 85 99 85 65 78 87 85 57 85 99?
85
What is the median of 72 90 85 84 91 78 94 86 82 78 86 78 95 90 88?
The median is 86.
What is the compatible numbers of 84-36?
85-35=50
What are the 5 consecutive numbers of 415?
The numbers are 81, 82, 83, 84 and 85.
What are the three consecutive numbers is 252 what are the three numbers?
83, 84 and 85 if you add them.
What would you choose mean median mode or range for the numbers 56 78 85 92 65 79 15?
Mean: 67.143 Median: 78 Mode: 56, 78, 85, 92, 65, 79, 15 Range: 77
What is the median of 97 85 92 and 86?
The idea is to sort the numbers, and pick the number in the middle as the median. In cases like this, when you have two numbers in the middle (the size of the set is even), take the average of those two numbers.
What is the median of these numbers 82 85 87 89 91 93 96 97?
The median is (89 + 91)/2 = 90
