Q: What would your median be if you had 84 and 85 as your numbers?

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The idea is to sort the numbers, and pick the number in the middle as the median. In cases like this, when you have two numbers in the middle (the size of the set is even), take the average of those two numbers.

meanAdd up the numbers and divide by how many there are: 87+75+89+81+90+73+85+96+65+92+78+79+83+85+79+90+86+72+74+88+81+85 = 1813There are 22 numbers.â‡’ mean = 1813 Ã· 22= 829/22â‰ˆ 82.41medianSort the numbers into order; the median is the middle number (if an odd number of numbers) or the mean of the middle two (if an even number of numbers): Sorted: 65, 72, 73, 74, 75, 78, 79, 79, 81, 81, 83, 85, 85, 85, 86, 87, 88, 89, 90, 90, 92, 96There are 22, so the median is the mean of the middle two which are the 11th (83) and 12th (85) numbers:â‡’ median = (83+85) Ã·2= 84modeThe number which appears the most often. Having sorted the list for the median, it can be seen that the one with the highest frequency appears three times: â‡’ mode = 85

The median for 85, 93, 95, 96, 98, 99, 100, 100 is 97. The number in the middle is 96, and 98. Add - 96 + 98 = 194 Divide - 194 ÷ 2 = 97

Let denote the missing number with x. So we have:(76 + 78 + 81 + x)/4 = 85(235 + x)/4 = 85(4)(235 + x)/4 = (4)(85)235 + x = 340235 - 235 + x = 340 - 235x = 105

Let the numbers be m & m+1 (consecutive) Hence their squares are m^2 & ( m + 1)^2 => m^2 & m^2 + 2m + 2 Hence Their sum is m^2 + m^2 + 2m + 1 = 85 2m^2 + 2m - 84 = 0 m^2 + m - 42 =0 Factor (m + 7)(m - 6) = 0 Hence the numbers are 6 & 7 .

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For median the list needs to be sorted into increasing order, but doing so also helps with the range and mode, so I'll do that first: {89, 76, 85, 76, 77, 84} → {76, 76, 77, 84, 85, 89} Mean: add them up and divide the sum by how many numbers there are: mean = (89 + 76 + 85 + 76 + 77 + 84) / 6 = 81 1/6 ≈ 81.167 Median: middle number when listed in order; if there are an even number of data items, then the median is the mean average of the middle two: There are 6 data items so median is mean average of middle two: median = (77 + 84) / 2 = 80 ½ = 80.5 Mode: the most frequent, it the number which occurs the most often. There can be more than one mode: mode = 76 as there are two of them and only 1 of all the other numbers. Range: the difference between the greatest and least numbers: range = 89 - 76 = 13

The median is 85.

The median is the average of 85 and 87, that is 86.The median is the average of 85 and 87, that is 86.The median is the average of 85 and 87, that is 86.The median is the average of 85 and 87, that is 86.

add them all up and divide by how many numbers there are so..... 85+92+84+85+96+95=? and divide by 6

The median is 86.

85

85-35=50

The numbers are 81, 82, 83, 84 and 85.

83, 84 and 85 if you add them.

Mean: 67.143 Median: 78 Mode: 56, 78, 85, 92, 65, 79, 15 Range: 77

The median is (89 + 91)/2 = 90

85 91 48 98 99 91 90 84 91 To find the median, first rearrange the numbers in rank order. That is from lowest to highest. Hence 48,84,85,90,91,91,91,98,99. Next we notice that there are nine terms. To find the median we than take the absolute middle term. In this case it is '91'. There are four terms to the left and right of the median term. NB If you had left the numbers in the original order, the median would have been '99', which is incorrect. NNB As an aside the MODE is also '91'. However, in this case it is found by looking for the term that occurs most frequently. In this case there are three lots of '91' , but only one of each other term. Hope that helps !!!!