9.
And the word is minus, not minis.
= 5x2+70-16+9x-2 = 5x2+9x+52 = 5x2+9x1+52 This implies coefficient of degree 1 is 9. Ans.
A fifth degree polynomial.
4
False
6 is the coefficient of n in this expression.
-6. And the word is still minus, not minis.
6
For a single term, the "degree" refers to the power. The coefficient is the number in front of (to the left of) the x.
The expression "X plus 5 x plus 2" can be simplified to "6x + 2". Therefore, the polynomial in standard form is 6x + 2.
it is 3. You are doing APEX right?
= 5x2+70-16+9x-2 = 5x2+9x+52 = 5x2+9x1+52 This implies coefficient of degree 1 is 9. Ans.
Yes. Before using the polynomial for any productive purpose, it would have to be cleaned up and simplified. In that process, the +3x4 and -3x4 would go away, and the highest-order term remaining would be the 4x3.
A fifth degree polynomial.
1, 8, -5 and 4 One could argue that 4 is not a coefficient, but a term of it's own. On the other hand, if you follow the pattern in the polynomial, you could argue that it's a coefficient of x0.
The actual equation itself is the polynomial. There is no polynomial for it, and your question doesn't really make sense.
It is a quadratic polynomial.
If the coefficients of a polynomial of degree three are real it MUST have a real zero. In the following, asymptotic values are assumed as being attained for brevity: If the coeeff of x3 is positive, the value of the polynomial goes from minus infinity to plus infinity as x goes from minus infinity to plus infinity. The reverse is true if the coefficient of x3 is negative. Since all polynomials are continuous functions, the polynomial must cross the x axis at some point. That's your root.