answersLogoWhite

0


Best Answer

1, 8, -5 and 4

One could argue that 4 is not a coefficient, but a term of it's own. On the other hand, if you follow the pattern in the polynomial, you could argue that it's a coefficient of x0.

User Avatar

Wiki User

13y ago

Still curious? Ask our experts.

Chat with our AI personalities

EzraEzra
Faith is not about having all the answers, but learning to ask the right questions.
Chat with Ezra
RafaRafa
There's no fun in playing it safe. Why not try something a little unhinged?
Chat with Rafa
LaoLao
The path is yours to walk; I am only here to hold up a mirror.
Chat with Lao

Add your answer:

Earn +20 pts
Q: What are the coefficients of x3 8x2-5x plus 4?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What is the factor of x3 plus x2 plus 4x plus 4?

x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)


Factor x3 plus 4x2 plus x plus 4?

x3 + 4x2 + x + 4 = (x + 4)(x2 + 1)


How do you find a cubic equation with integral coefficients that has the roots 2 and 4 plus i?

If it has integral coefficients and 4+i is a root then its conjugate, 4-i must also be a root. So the equation is f(x) = (x-2)*(x-4-i)*(x-4+i) where each factor is x minus a root. Then multiply these out. = (x-2)*(x2 - 8x + 17) = x3 - 2x2 - 8x2 + 16x + 17x - 34 = x3 - 10x2 + 33x - 34


X3 plus x2 minus 6x plus 4?

x3 + x2 - 6x + 4 = (x - 1)(x2 + 2x - 4)


How do you solve x3 plus 4x2 plus 6x plus 24?

x3 + 4x2 + 6x + 24 = (x2 + 6)(x + 4)


How do you factor x3 plus 5x2 minus 16x minus 80?

To factorise x3 + 5x2 - 16x - 80 I note that -80 = 5 x -16 and 5 & -16 are the coefficients of x2 and x. Thus I have: x3 + 5x2 - 16x - 80 = (x + 5)(x2 - 16) and the second term is a difference of 2 squares, meaning I have: x3 + 5x2 - 16x - 80 = (x + 5)(x + 4)(x - 4)


Find factors of x3 plus 12x2 plus 48x plus 64?

x3 + 12x2 + 48x + 64= (x + 4)(x2 + 8x + 16)= (x + 4)(x + 4)(x + 4)= (x + 4)3


Is x3 plus 4 a trinomial?

no it is not. it is only a binomial.


The coefficients in the expansion of (x plus y)4 are?

1,4,6,4,1


What is the quotient and remainder if any when the expession 4x4 -x3 plus 17x2 plus 11x plus 4 is divided by 4x plus 3?

Dividend: 4x4-x3+17x2+11x+4 Divisor: 4x+3 Quotient: x3-x2+5x-1 Remainder: 7


What is x3 plus x plus 1 divided by x-1?

4


How do you factor x3-3x2 plus 4?

x3 - 3x2 + 4 Since the coefficients of the odd powers of x (=1) is the same as the sum of the even powers (-3+4=1), then x = -1 must be a root. That is to say, (x + 1) is a factor. So you can rewrite the expression as x3 + x2 - 4x2 - 4x + 4x + 4 = x2(x + 1) - 4(x + 1) + 4(x + 1) = (x + 1)*(x2 - 4x + 4) = (x + 1)*(x - 2)2