6
(x, y) = (-3, -3) or (3, 3)
x= z2 - 3
x - y = -3 -y = -x - 3 y = x + 3 y-int. = 3 x-int. = -3
x=3 y=3.5
x=4 y=x+3 y=4+3 y=7
3
6
(x, y) = (-3, -3) or (3, 3)
It depends on how y depends on x.
x= z2 - 3
x+y=3 y=3-2x so x+3-2x=3 so x=0 0+y=3 so y=3
x - y = -3 -y = -x - 3 y = x + 3 y-int. = 3 x-int. = -3
If x+y = 3 and y times x = 2 then y = 1.
x=3 y=3.5
0
y = xz where x = 3, z = 10 y = 3 x 10 = 30