3x+5 = 2x+13 3x-2x = 13-5 x = 8
2x + 1 = -5 so 2x = -6 so that x = -3 Then 3x - 4 = 3*(-3) -4 = -9 - 4 = -13
6x2 + 10x = 2x*(3x + 5)
2x + 5 + 3x = 25 5x + 5 = 25 Subtract 5 from both sides: 5x = 20 Divide both sides by 5: x = 4
Here is how you solve this problem... 5x*4-3x*5*2x-9= (Combine like-terms) 5x-3x*2x= 2x*2x=(2x)2 (Add the rest of the problem) (2x)2*4*5-9=(2x)2*20-9 (2x)2*11 (2x)2 *11= your answer
2x + 5
Presumably, this is an equation in finding the value of x 3x+5/4 = -2x+15 3x+1.25 = -2x+15 3x+2x = 15-1.25 5x = 13.75 x = 2.75
3x - y = 3y = 2x + 2Put the value of y in the 1st equation:3x - y = 3 it will be -->3x - ( 2x + 2 ) = 33x - 2x - 2 = 3x - 2 = 3X = 5Put the value of X in the 2nd equation so as to find the value of Y :y = 2x + 2y = 2(5) + 2y = 10 + 2Y = 12
x = 5 ========== 3x - 9 = -2x + 16 Balance the equation by adding 2x and 9 to both sides: 3x + 2x = 16 + 9 5x = 25 Divide both sides by 5 to get value for x: x = 5
3x+5 = 2x+13 3x-2x = 13-5 x = 8
2x-5=3x+6 -5-6=3x-2x -11=x x=-11
2x+12-3x = 5 2x-3x = 5-12 -x = -7 x = 7
(x + 1) / (2x3 + 3x + 5) --- Can't depict long division here, but you can work this out by seeing if (x + 1) is a factor of (2x3 + 3x + 5). If it is, then the answer will be 1/(the other factor). In this case, that is true. (2x3 + 3x + 5)/(x + 1) = 2x2 - 2x + 5, so the term term above is equal to: 1 / (2x2 - 2x + 5)
2x + 1 = -5 so 2x = -6 so that x = -3 Then 3x - 4 = 3*(-3) -4 = -9 - 4 = -13
2x+12-3x = 5 2x-3x = 5-12 x = -7
2x(3x-5) = 6x2-10x
2x+3 = 3x+5 2x-3x = 5-3 -x = 2 x = -2