Points: (-6, 1) and (-2, -2) Distance: 5 units
(3-1)2 + (5-8)2 = 13 and the square root of this is the distance between the points
The difference between these increases is that 1% increase gives the 101% increase of the original amount of points while 100% basis increase gives the 200% increase of the original amount of points.
End points: (10, -4) and (2, 2) Midpoint: (6, -1) Distance from (6, -1) to (10, -4) = 5 Distance from (6, -1) to (2, 2) = 5 Equation of the circle: (x-6)^2 +(y+1)^2 = 25
The answer is b+1. Therefore the algebraic expression for this is b+1
Distance = (9-5)2+(-6-1)2 = 65 and the square root of this is the distance between the points which is about 8.062257748
square root of (5-9)^2+(1+6)^2
square root of (5-9)^2+(1+6)^2
the area of a rectangle with width x and length 6x is 6x^2 what does the coefficient 6 mean in terms of the problem
1
Points: (1, -2) and (1, -5) Distance: 3 units by using the distance formula
11 points
1
Points: (-6, 1) and (-2, -2) Distance: 5 units
Points: (2, 1) and (14, 6) Distance: 13
The distance between two points on a coordinate plane is calculated using the distance formula: Distance = √((x2 - x1)^2 + (y2 - y1)^2) In this case, the coordinates of the two points are (7, 1) and (7, 3). Since the x-coordinates are the same, we only need to calculate the difference in the y-coordinates, which is (3 - 1) = 2. Plugging this into the distance formula gives us: Distance = √((0)^2 + (2)^2) = √4 = 2. Therefore, the distance between the two points is 2 units.
If you mean points of (1, -2) and (-9, 3) then the distance is about 11 units using the distance formula