It will be a straight line that is parallel to the y axis on the Cartesian plane
Yes. A quadratic function can have 0, 1, or 2 x-intercepts, and 0, 1, or 2 y-intercepts.
The x- and y-intercepts of a function are the points at which the graph of the function crosses respectively the x- and y-axis (ie. y=0 and x=0).
The x coordinate for all y intercepts is 0, just as the y coordinate for all x intercepts is 0.
Suppose the equation of the parabola is y = ax2 + bx + c Now, where the parabola crosses the x-axis (the x intercepts), the value of y must be zero (that is what crossing the x-axis means). If the discriminant, b2 - 4ac is less than zero, y has no real roots. This means that there is no real value of x for which y equals zero and so the parabola has no x intercepts. If the discriminant is zero then the parabola only touches the x-axis - at (-b/2a,0). If the discriminant is greater than zero, there are two distinct intercepts. If a>0 then the parabola is shaped like a U and is wholly above the x-axis. If a<0 then the parabola is an upturned U, wholly below the x axis. If a = 0 the quadratic term disappears and the function is a straight line, not a parabola.
It intercepts the y axis at (0, 5) and it intercepts the x axis at (-2.3, 0) passing through the I, II and III quadrants
Yes. A quadratic function can have 0, 1, or 2 x-intercepts, and 0, 1, or 2 y-intercepts.
5x²=0 X=0 the function y=5x² only intercepts x when x = 0
yes * * * * * No, it is not. In a direct variation, if one of the variables is 0, the other MUST also be 0. In a linear function, they will be the intercepts.
The x- and y-intercepts of a function are the points at which the graph of the function crosses respectively the x- and y-axis (ie. y=0 and x=0).
A circle can have 0, 1, or 2 x-intercepts and 0,1, or 2 y-intercepts, bringing the total to 0, 1, 2, 3, or 4 intercepts.
The x coordinate for all y intercepts is 0, just as the y coordinate for all x intercepts is 0.
The intercepts of 2x + 3y - 6z = 30 are(15, 0, 0), (0, 10, 0) and (0, 0 , -5).
The intercepts of 2x + 3y - 6z = 30 are(15, 0, 0), (0, 10, 0) and (0, 0 , -5).
Just one. It's at the origin. (0, 0)
Given the linear equation 3x - 2y^6 = 0, the x and y intercepts are found by replacing the x and y with 0. This gives the intercepts of x and y where both = 0.
They are positive straight lines that intercepts the origin and have no y intercepts.
for the equation:5x + 10y = 20, the two intercepts are:x = 0 , y = 2 or (0,2)y = 0 , x = 4 or (4,0)The graph is a straight line passing through the two intercepts (0,2) and (4,0)