The intercepts of 2x + 3y - 6z = 30 are(15, 0, 0), (0, 10, 0) and (0, 0 , -5).
x: x = 15 y: y = 10 z: z = -5
The result will be a plane that intercepts the x-, y-, and z-axes at +9, +6, and +3, respectively.
The list of choices that accompanies the question is really short.2x + 3y + 6z = 54At the y-intercept, 'x' and 'z' are zero.3y = 54y = 18
Since there are no given triplets, none of them!
3x 3y + 6z = 12
6z-513 = -507
you treat the letters like numbers i.e if x=4y, rearrange for y solution: divide both sides by 4 therefore y=1/4 x example 2: 6z+x/y = 2x-y rearrange for z solution: multiply both sides by y: 6z+x = y(2x-y) 6z+x = 2xy-y2 Take away x from both sides: 6z = 2xy-y2-x divide both sides by 6: z= 1/6(2xy-y2-x) done!
(x + 6z)(x - 6z)
6z + 28 = 12z + 10 18 = 6z 3 = z