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The intercepts of 2x + 3y - 6z = 30 are(15, 0, 0), (0, 10, 0) and (0, 0 , -5).

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Adolfo Bartoletti

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โˆ™ 2021-11-21 21:34:14
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Q: What are the intercepts of 2x + 3y โ€“ 6z = 30?
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Related questions

What are the intercepts of 2x plus 3y and ndash 6z 30?

The intercepts of 2x + 3y - 6z = 30 are(15, 0, 0), (0, 10, 0) and (0, 0 , -5).


What are the intercepts of 2x 3y-6z equals 30?

x: x = 15 y: y = 10 z: z = -5


Graph the equation 2x plus 3y plus 6z equals 18?

The result will be a plane that intercepts the x-, y-, and z-axes at +9, +6, and +3, respectively.


Which of these ordered triples indicates where the plane cuts the y-axis for this equation 2x plus 3y plus 6z equals 54?

The list of choices that accompanies the question is really short.2x + 3y + 6z = 54At the y-intercept, 'x' and 'z' are zero.3y = 54y = 18


Which of these ordered triples indicates where the plane cuts the y axis for this equation 2x plus 3y plus 6z equals 54?

Since there are no given triplets, none of them!


What is 6z?

6z =


What is 6z-513?

6z-513 = -507


What is the factored form of x2-36z2?

(x + 6z)(x - 6z)


What is the sum of -5x plus 7y-6z?

-5x+7y-6z


What does this equal 6z plus 28 equals 12z plus 10?

6z + 28 = 12z + 10 18 = 6z 3 = z


How do you rearrange formulae?

you treat the letters like numbers i.e if x=4y, rearrange for y solution: divide both sides by 4 therefore y=1/4 x example 2: 6z+x/y = 2x-y rearrange for z solution: multiply both sides by y: 6z+x = y(2x-y) 6z+x = 2xy-y2 Take away x from both sides: 6z = 2xy-y2-x divide both sides by 6: z= 1/6(2xy-y2-x) done!


What is the answer of 12zยณ/6z?

2


6z plus 28 equals 12z plus 10?

6z+28=12z+10 6z-12z=10-28 addition property of equality. -6z=-18 simplification z=3 multiplication property of equality.


What is the algebraic expression for 8x plus one-half the difference of y and 6z?

14


What is 6z equals 17?

If 6z=17, divide both sides by 6 z=17/6


What is the solve two step equation of -6z plus 16 equals 52?

-6z + 16 = 52 subtract 16 from each side -6z = 36 divide by -6 z = -6


How do you solve the equation 6z-8-2 plus 3 equals 0?

6z - 8 - 2 + 3 = 0 combining all the constant terms: 6z -7 = 0 adding 7 to both sides: 6z = 7 dividing both sides by 6: z = 7/6


What is 17z plus 34 equals 6z plus 5?

17z + 34 = 6z + 5 17z - 6z + 34 = 6z - 6z + 5 11z + 34 = 5 11z + 34 - 34 = 5 - 34 11z = -29 11z/11 = -29/11 z = -2 7/11 or -29/11 Double check your answer: 17z + 34 = 6z + 5 17(-2 7/11) + 34 = 6z + 5 -44 9/11 + 34 = 6z + 5 -10 9/11 = 6z + 5 -10 9/11 = 6(-2 7/11) + 5 -10 9/11 = -15 9/11 + 5 -10 9/11 = -10 9/11 17z + 34 = 6z + 5 when Z = -2 7/11


-6z to the 3rd power?

-216z3


How to solve the system of equations 4x plus 3y plus 2z equals 34 and 2x plus 4y plus 3z equals 45 and 3x plus 2y plus 4z equals 47?

4x + 3y + 2z = 34; 2x + 4y + 3z = 45; 3x + 2y + 4z = 47 First, eliminate terms in z from 2 of the equations, by muliplying first equation by 2 and subtracting third equation from the answer: 8x + 6y + 4z = 68, subtract leaving 5x + 4y = 21 (equation 4) Similarly multiply the first equation by 3 and the second by 2 giving 12x + 9y + 6z = 102 and 4x + 8y + 6z = 90 Subtract again and we have 8x + y = 12 or y = 12 - 8x Substitute this in equation 4 gives 5x + 4(12 -8x) = 21 Simplify: 5x + 48 - 32x = 21 = -27x = -27 so x = 1 y = 12 - 8x so y = 4 and in one of the original equations 4 + 12 + 2z = 34, ie 2z = 34 -16 so z =9 Check: 2x + 4y + 3z = 2 +16 + 27 = 45 and 3x + 2y + 4z = 3 + 8 + 36 = 47 QED!


15z plus 5 plus 6z equals?

15z+5+6z=0 21z+5=0 z=-5/21


What is 6z plus 4-4z equals 6 plus z-7 simplified?

6z-4z-z = 6-7-4 z = -5


How do you prove Equation -6z plus 2 equals 3z plus 4z plus 28 solved for z z equals -2?

-6z + 2 = 3z + 4z + 28 Add 6z to both sides: 2 = 3z + 4z + 28 + 6z = 28 + 13z Subtract 28 from both sides: - 26 = 13z Divide both sides by 13: -2 = z


How do you solve these equations by substitution 2x-5y plus 2z equals 16 3x plus 2y-3z equals -19 4x-3y plus 4z equals 18?

If you mean: 2x-5y+2z = 16 and 3x+2y-3z = -19 and 4x-3y+4z = 18 then the solutions are found as follows:- 3(2x-5y+2z = 16) => 6x-15y+6z = 48 2(3x+2y-3z = -19) => 6x+4y-6z = -38 Adding the above: 12x-11y = 10 thus eliminating z 4(3x+2y-3z = -19) => 12x+8y-12z = -76 3(4x-3y+4z = 18) => 12x-9y+12z = 54 Adding the above: 24x-y = -22 thus eliminating z 2(12x-11y = 10) => 24x-22y = 20 1(24x-y = -22) => 24x-y = -22 Subtracting the above: -21y = 42 thus eliminating x If: -21y = 42 then y = -2 So by substitution: x = -1, y = -2 and z = 4 Check: (2*-1)-(5*-2)+(2*4) = 16 Check: (3*-1)+(2*-2)-(3*4) = -19 Check: (4*-1)-(3*-2)+(4*4) = 18


42 equals 6z?

z equals 7

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