The intercepts of 2x + 3y - 6z = 30 are(15, 0, 0), (0, 10, 0) and (0, 0 , -5).
It can be simplified to: 2x+33
2x + 30 = 4x + 10 Subtracting 2x from each side, 30 = 2x + 10 Subtracting 10 from both sides 20 = 2x Dividing both sides by 2 10 = x x = 10
To find the intercepts of the equation (2x + 3y - 6z = 30), set two variables to zero and solve for the third. For the x-intercept, set (y = 0) and (z = 0): (2x = 30 \Rightarrow x = 15) (intercept: (15, 0, 0)). For the y-intercept, set (x = 0) and (z = 0): (3y = 30 \Rightarrow y = 10) (intercept: (0, 10, 0)). For the z-intercept, set (x = 0) and (y = 0): (-6z = 30 \Rightarrow z = -5) (intercept: (0, 0, -5)).
If: 3x+20 = 2x-10 Then: x = -30
30+12x = 6(5+2x)
The intercepts of 2x + 3y - 6z = 30 are(15, 0, 0), (0, 10, 0) and (0, 0 , -5).
It can be simplified to: 2x+33
This website isn't equipped to reproduce most mathematical symbols in the questions. I'll see if I can translate. 2x + 3(x - 10) = 45 2x + 3x - 30 = 45 5x - 30 = 45 5x = 75 x = 15 Check it. 2(15) + 3(15 - 10) = 45 30 + 15 = 45 It checks.
x: x = 15 y: y = 10 z: z = -5
2x + 30 = 4x + 22 Subtracting 2x from both sides, 30 = 2x + 22 Subtracting 22 from both sides, 8 = 2x Dividing both sides by 2, 4 = x x = 4
2x + 30 = 4x + 10 Subtracting 2x from each side, 30 = 2x + 10 Subtracting 10 from both sides 20 = 2x Dividing both sides by 2 10 = x x = 10
If: 3x+20 = 2x-10 Then: x = -30
30+12x = 6(5+2x)
2x + 6 - 6x = 30= 6 - 4x = 30= -4x = 24= 4x = -24= x = -6
2X+5Y+30=0 So you subtract 30 from each side. 2X+5Y+30-30=0-30. So you know 2X+5Y=-30. now there are many different possibilities for X and Y unless there is a specification. here are some possibilities=X=0,Y=6 or X=A5,Y=0 or X=5,Y=4
If the question is in the context of angles, then x + 20 + x + 10 = 90 ie 2x + 30 = 90 or 2x = 60 which gives x = 30
X=30 2x+2x+x+30=180; All of the angles in a triangle always add up to 180. Therefore 5x+30=180; subtract 30 to be 5x by itself. Therefore 5x=150; divide by 5 to find x. Therefore X=30 2(30)+2(30)+30+30=180